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Prove that `((4n)C_(2n))/((2n)C_n)=[1.3.5....(4n-1)]/[1.3.5...(2n-1)]^2`
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show that C ( 4n , 2n ) / C ( 2n , n ) = { 1. 3 . 5 .... (4n-1 ) / {1 . 3 . 5 ....(2n-1 ) } ^ 2
simplify C⁴ⁿ₂ₙ / C²ⁿₙ = {1.3.5.....(4n-1) } / {1.3.5......(2n-1)}²
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