Solve this Cubic Equation Using NO FUSS FACTORS | Fast & Easy Method

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I've never seen the no fuss factoring method before, so that's something new. Not sure I actually like it compared to just figuring out the factors easily enough by looking at the few options available, but it's always good to have extra tools in the toolbox.

jayquirk

The factoring method used on the quadratic is frequently called the "Master Product" method

johngreen

21x^2 -5x -6. 21 x -6 += -126. Look at pairs of numbers which multiply to -126 and have a sum of -5.
They turn out to be -14 and +9*. Re-write the quadratic 'splitting' the middle term using these two numbers.
21x^2 -14x + 9x -6. Take the greatest common factor of the first two terms and then the last two terms.
7x(3x -2) + 3(3x-2). So (3x-2) is now a common factor of the two terms. Factor it out...
(3x-2)(7x+3). Easy, repeatable 3 steps. *The only 'search and destroy' is finding the two numbers. I would tell my students to just start writing the pairs and the correct one will leap off the page..
126, 1...63, 2...42, 3...21, 6...18, 7...14, 9 Boom!! It was called the 'decomposition method'.

davecotterell

no fuss factoring is a new method for me. thanks for sharing! :)

king_haku

In this video you solved the first value of x (zero) then solved the quadratic equation to find the other values of x. However in the video 'Ramanujan's Problem' you didn't attempt solve the cubic polynomial to get alternative solutions. Can you explain why please?

sr

got it, thanks for the challenge bro, keep em comin

math

Brilliant sir. You make it seem so easy.

zahidbanatwalla

x = 0 and it becomes to quadratic eqn.

sngmn

I got as far as multiplying both sides by 7 and after that I didn't have a clue! Great explanation by you.

davidfromstow

It's obvious, in my head it gives S={-3/7;0;2/3}, I have at least two ways to do that. More than 7 mn, I don't have enough Mo for now to watch that. I have to see for now how to make it happen easier.

lazaremoanang

Why not use the quadratic formula? It’s so easy and it works for every quadratic equation-

stonerdave

I can bare follow this, much I don't understand. However, I feel like I'm watching a magical fairy tale where everyone lives happily ever after.

UristMcFarmer

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