How to find the next term in this sequence | Learn Math with Zain | Shorts

#sequence #nextterm # YouTubeShorts

[Infurnal]

The hidden sequence in the sequence makes alot of sense

[yumi.cutixx]

oh that makes sense. im surely gonna fail our math exam if i didnt knew this 😭 thank you so muchh

[Deathranger]

This only works if the sequence is constructed for it to work like this. Not all sequences are defined by a polynomial (and in fact, most aren’t).

[Messiy_Gaming]

wow this will be very useful to day to day things

[Joshua-qfvq]

Now how exactly would you find the nth term in this?

[ahmedsakr]

How can i get if the numbers randomly ???

[papatelenor]

Man what will be formula for this sequence?

[gklalaxo]

Thank you so much!I learnt it in class but had no idea😅
New subscriber btw :^

[ahmedrassoul]

Hello I have a question
What is the sequence given has only 4 terms and we must find the nth terms
The problem in such question is once you get to the 3rd sequence we must stop because we don't have other numbers to find the difference between them.
What should I do in this situation?

[JohnKnox-dixl]

Funny had this same one today in an assessment lol glad I picked 34 out 😂😂

[KristoffKristoff]

But where did you get the +7 can you kindly explain please, thank you

[memethecutefox]

U explain more better then my math teacher

[leahpanao]

Omg...now ko lng nagets kung kelan grad. nako ng h.s🤣🤣🤣🤣

[mechellmarco]

Thank you so much!!! But I olso like decrease next term

[maliajane]

Make good use of the internet guys 😌😂💞

[areeselseed]

i had so much difficulty in this and i understood how to do it in 1 min great video

[ernarnurbek]

firstly, whats the track is going on?)) its goodly suits for this doing trick for this solution))).... did also affect to someone of U also?))....

[Raze-nfqe]

I already know how to find the answer but honestly, this post made me confused

[WheresMyGlassesYT]

I think the formula for this is
an = 3.5n² - 6.5n + 4

[djdialjockey]

These are very typical in the local electrician union's application test.