Acid-Base Titration

Any introductory chemistry class will include titrations, and to do these, you have to do math. But you get to see pretty colors, too! Here's a quick run through of the stoichiometry of it all.

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[vanityromano]

I want to cry with joy at how easily you explained this, thank you for alleviating a huge frustration!!!

[BebeZaharasBeignets]

Professor Dave, you’re a lifesaver. If I get accepted for transfer at my dream university, graduate, then have the life I’ve always wanted I want you to ordain my wedding.

[hamzamalik]

Brilliant teaching. Really appreciate the thought and effort made into making these videos.

[elizabethcolon]

If you were my real professor i'd have 105 in chem you explain so well give great examples and you make sure we understood what you showed us by making us do an exercise ourselves. What great way of teaching!

[JasonChanMarioKartProPlayer]

Molarity times Volume (MV)before titration= MV after titration
75/1000 x 0.5 = 165/1000 x M
M= 0.2272727...
This also worked and my teacher told us to use this method

[yanapat]

thanks pookie i missed like a week of school and didn’t even understand this lab

[meganxu]

i want the 5 hour version of the jingle

[rokotrstenjak]

you forgot to do molar ratio for the first problem. you should've multiplied the moles of H2So4 by 2 due to the 1:2 ratio. Thank you

[beckya.]

Thank you for NOT over complicating your explanations. 🙏🏽

[yuiii]

Wait, did I just finally understand the topic in under 2 minutes and 40 seconds? Yes. Thank you so much prof Dave! You made it so much easier to understand!

[a_human_x]

8 years and these videos are still saving my life.

[rohmanjakarta]

On the example, the mol of base should be two times the acid so the mol of base is 0.0696

[pocketrocket]

I missed the part where you explained the titration?

[aionioshagiazo]

Hi Prof. Dave, I have a question: Should we not consider the balanced equation of Sulfuric acid and Sodium Hydroxide when we do the calculation? The ratio of acid/base should be 1:2, then the mole of base should be 0.0348 x 2 = 0.0696...please advice thanks!

[andrewjustin]

1:40 Mr. Dave, perhaps you missed the point on using the stoicheometrical ratios. Besides you did not even balance the equation. Have a look at this:
2NaOH + H2SO4 ---> 2H2O + Na2aSO4

That implies you had to multiply 0.0348mol with 2, then divide with its volume. Because we need 2 miles of the base to neutralize just 1 mole of the acid, suggesting the resilience of the acid.
So, 0.0348mol×2= 0.0696mol
Then 0.0696mol/0.025L
= 2.784M

[kripashankarshukla]

Sir your theme song and your explanation both are the best.

[linzelj]

You might want to fix your mole ratio at time = 1:38. Its a 1:2 the base would be twice the 0.0348 and hence double 1.39 as indicated.

[rosieleaverton]

I was stressing really bad over my homework because the other resources my teacher gave weren't helping, but your video made it so incredibly clear. Thank you!!

[lucasvdb]

This is exactly what I was looking for, tysm!

[lottajarvi]

Thank you so much, your videos have been super helpful as I have been studying for my big chemistry exam!