17.2 Acid-Base Titrations and Titration Curves | General Chemistry

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Chad provides an introduction to titrations and titration curves. The lesson begins with a description of a Strong Acid / Strong Base titration curve. The terms analyte, titrant, equivalence point, and indicator are all introduced and defined. It is explained how a the titration of a strong acid with a strong base produces water and a neutral salt explaining why the pH is equal to 7 at the equivalence point. An example calculation of the concentration of the analyte from the equivalence point is performed.
Next, a description of a Weak Acid / Strong Base titration is provided including the fact that the pH is greater than 7 at the equivalence point as the products are water and a basic salt. Also described is the half-equivalence point where half the amount of titrant required to reach the equivalence point has been added. At this point the concentration of the conjugate acid is equal to that of the conjugate base. According to the Henderson-Hasselbalch equation, pH = pKa and pOH = pKb and this point in the titration can be used to quickly approximate the pKa of a weak acid or the pKb of a weak base.
Finally, a description of a Weak Base / Strong Acid titration is provided including the fact that the pH is less than 7 at the equivalence point as the products are water and an acidic salt. Just as in the Weak Acid / Strong Base titration, the half-equivalence point can be used to quickly approximate the pKa of a weak acid or the pKb of a weak base.

00:00 Lesson Introduction
00:59 Strong Acid-Strong Base Titration Curve
11:53 Weak Acid-Strong Base Titration Curve
23:16 Weak Base-Strong Acid Titration Curve

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i love you so much chad! i don't know how you get this much motivation to teach such a complex subject with this ease! greatest chemistry teacher of all time

divital
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you have made my chem lecture slides even more useless than they were thank you so much for all your videos. if i knew where u lived i would buy u chocolate & wine and a newtons cradle or something idk but ur the best dude

VV.M
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AMAZING video for final exam review, props to you man!!!

Soppage
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You made the explanation so clear!!!! Really helped me understand acid base titrations :))

danielkim
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Excellent lecture Chad - so easy to understand. You are an awesome teacher.

venugopalmiyyapuram
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Just wanted to thank you. I wanted to review this part of solution chemistry and you nailed it.

VelkozSupport
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Your videos are great and I really admire the way you make science coherent. Also, I love your shirt!

dunchollingsworth
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Basically spent my whole spring beak with you. These videos are extremely helpful! I used to dread doing chem but learning chem from you makes it exciting to solve problems, thank you so much!! If you could, can you pleasee go over titration(curve) of polyprotic acids?

tranphu
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This is going to help so many students

dom
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Chad you''re amazing! best teacher ever!

AmitMusicStaz
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wow i really love ur videos, it gets down to the small details. love it

shavoniilloyd
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Thank you for this! Do you by any chance have a video for the titration of polyprotic acids and bases, please?

FrontierThesisYU
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Thank you so much ❤️💕 I enjoyed this lecture..

harry-uhyg
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Around 23:00, you say that the moles of Acid and Conjugate Base are equal, but is it more accurate to say that the Molarity of the Acid and its Conjugate base are equal at the equivalence point? Is it true that at the half equivalence point, the concentration and moles of Acid and Conjugate base are equal? Or can the concentration of the Acid and Base be different from the moles of Acid and Conjugate Base? I hope my questions make sense.

saqibkhan
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Thank you so much, this is extremely helpful. Quick question, at the half-equivalence point of each of the last two titration curves, is the region of plus or minus 1 around this point the buffering region?

TheUltimateSayain
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Thanks, very patiently and thoroughly explained.

balajikannan
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sir, i understand why pka is equal to ph in the 1/2 titration point. but we can not say the same to poh and pkb in the equivalent point right? after all it depends on the concentration, or did i just miss understand your explaination?

aszasq
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about to have my final exam for gen II chem, I'll let you know if I cooked or got cooked

jbecuti
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Im kinda stuck with the Equivalance point part. On the graph, it shows you have to ad 20mL of NaOH. But when you were describing the 1/2 equivalnce point, in the initial equation you wrote 10 mol HF+ 10 mol NaOH. Can you clarify that part?

pchacksu
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Sir when we are performing titration of strong acid with a strong pink color indicates equivalence point or end point ??
As phenolphthalein gives pink color in basic medium and colorless in acidic medium light pink color would be in neutral medium ?

sumairaimaan