Limits of Functions of Two Variables

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Hey this video was fantastic! I'm taking multivariable calculus for the first time and my professor has the worst possible teaching methods so I really appreciate this!

aegurak
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very helpful. It took me a while to find a video that explaned paths as opposed to basic algebra tricks that only work for some functions.

seth-langendoen
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when my lecturer tried to explaain these, he bored us to absolute death and made it look like a horrible endless thing to figure out, yet this was simmple to understand, and didnt take half as long to explain. there should just be a youtube college run by you guys lol

hohner
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@leemonastesse84 It is x^2 + x^2 = 2x^2. The path is y = -x, so y^2 = (-x)^2 = x^2. The denominator along the path would be x^2 + x^2 = 2x^2. Notice the numerator is xy = x(-x) = -x^2. Hope that helps.

Mathispoweru
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This is the only thing I was having trouble with. Midterm in about 5 hours. You're a saint!

DauntedMelodies
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Thank you for doing non lim (x, y) -> (0, 0) problems! Very helpful.

mohamedhamdy
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The second example does how a limit that DNE. If you have a suggested example, I would definitely consider adding it.

Mathispoweru
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I don't get how you know which paths to take...

diamondz
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In your second example you said as the path y=-x the denominator is x^2+(-x^2)= 2x^2

How is that possible if you're adding a negative, that makes no sense. They should be zero right?

stevenhamilton
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in finding the limit of a function when you replace f(x, y) can you use any function? My assumption is that you can. can you replace y, for example, with x^3 or sqrt(x) or any other arbitrary function. Or does it have to be in the domain of f(x, y). If so, how would you know which function to use for approaching the limit?

macmos
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How does the denominator equal (2x^2) at the 7:25 mark. I see a x^2 - x^2. Can someone tell me if this is me or the video that made the mistake. Thank You!

leemonastesse
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Excellent great source in corona pandemic.

gorrelaakhil
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great slides , it was helpful, but I hope you make a second advanced video for those who want more, it can contain nice paths like : y=mx, that detemines if the function D.N.E as it is dependent on mx,
It would be great also, if the second video covers some trig functions
Best Regards

AhmedKMoustafa
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great slides , it was helpful, but I hope you make a second advanced video for those who want more, it can contain nice paths like : y=mx, that detemines if the function D.N.E as it is dependent on mx,
It would be great also, if the second video covers some trig functions
Best Regards

mohamedhamdy
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I agree. If you approach it from y = x, the value of the limit become 0.5 which would suggest that the limit does not exist at this point.

jorijgijrgij
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You explain this very nice, the graph is very necessary, anyone know what software can make this functions plots ?

OscarFernandez
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why are you choosing only y=x or -x while other paths are also possible like y=x^2 and many more????

nishantcharas
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@ 8:27 without graphing tools how would you know if the graph is continuous at (4, 2)

sksoh
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although y=x passes through that point, it is jus a line parallel to x-y plane.... how can prove the limit??

yuhaooo
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3:00
Did you point out the coordinate (1, 1, 1)? I thought (x, y) was 2D, on the xy plane. Why did you go into space for the point (1, 1)?

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