Linear Algebra 14TBD: Derivation of the 3x3 Determinant

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Loving these insights into determinants. I was just taught to remember the rules of calculating them and told it was a test for whether linear transformations are singular or not.

Hythloday

Sir! I don't understand how you derrived the result at 2:42 in this video!

jaatkumar

at about 2:05: when did we encounter this matrix before?

terryphi

When did we determine that if the first column has zeroes in the second and third rows, that we only have to look at the submatrix (entries 22, 23 and 32, 33) to determine whether the columns were linearly independent? I think I'm repeating the question by Terry Price - 2 years without an answer about the 2:05 in the video.

solfeinberg

Do you have an inductive proof for the Leibniz determinant formula using the method presented in the video?

robertschumann

I am getting the same expression for the determinant, except I have a 'd' multiplying the whole thing.

stepsvideos

+MathTheBeautiful
dont get it why multi "a" to get rid of denominator, don't we assume "a" is non-zero ?

thentust

Why 3x3 matrix determinant calculated in this method....?

saththiyambharathiyan

How can we show that this is the oriented volume of the parallelepiped spanned by the column (or row) vectors?

johnhippisley

I don't understand how you did that subtraction.

terryphi

i have no idea how did you cancel alphabets and got this matrix, please anyone can you show the steps

hariharanramamurthy

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