Calculus, derivative of inverse sine

Calculus, derivative of inverse sine,
Calculus, derivative of arcsin(x),
Calculus, derivative of sin^-1(x)

[shanepender]

I wish you would explain why Cos(Sin^-1(x)) is equal to the square root of 1-x^2. That was my whole reason of clicking on this video. Other than that, your explanation of everything else was fantastic.

[nepasdisponible]

2:39

Finally, he derived d/dx (sin x ) = 1/cos ( sin^-1 X).

Since he mentioned sin^-1 x = theta, 1/cos (sin^-1 x)= 1/cos ( theta).

We know that, sin^2 (theta) + cos^2 (theta) = 1,
and cos (theta) = sqrt of 1- sin^2 (theta).

Also, sin (theta) = x.

So the answer is
1/ sqrt of 1- x^2.

[joshparchure]

You can’t just skip the last part of the proof, what’s the point?

[davidsan]

I love how he just throws a random proof in at the end and goes "ta-da!" haha

[jayy_cobbe]

I am obsessed with how he dextrously interchanges the pens. How cool is that xd

[sousacanfly]

awesome explanation, can't understand the downvotes Great job explaining.

[SeemaSharma-cizg]

Thanks for telling me everything that I already know🙃

[hamzasheikh]

at the end i can, t understand i, m confuess

[lalitmishra]

What language r u speaking sir I can't understand

[sahilhooda]

Bhaji sin so sin inverse aise ni cancel kr skte

[TrRick]

You have made mistakes in the list line bruh. Rest of them are pretty helpful.