Normal Force on a Hill, Centripetal Force, Roller Coaster Problem, Vertical Circular Motion, Physics

This physics video tutorial explains how to calculate the normal force at the bottom and at the top of the hill given the speed and radius of the circular hill. This video provides the free body diagram needed to derive the formulas to calculate the normal force at those positions. In addition, this tutorial discusses how to find the minimum speed that a roller coaster must have so passengers don't fall out and the maximum speed an object can travel on top of a hill without losing contact with the surface. The normal force provides the centripetal force in these problems. This video contains plenty of examples and vertical circular motion practice problems.

Circular Motion - Formula Sheet:

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Static Friction & Centripetal Force:

Normal Force on a Hill:

Banked Turn Physics Problems:

Non-Uniform Circular Motion:

Gravitational Force:

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Universal Law of Gravitation:

Gravitational Acceleration:

Gravitational Field Strength:

Satellite Speed:

Kepler's Third Law of Motion:

Circular Motion Review:

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Kinetic Energy and Potential Energy:

Work, Energy, and Power:

Final Exams and Video Playlists:

Full-Length Videos and Worksheets:

Physics PDF Worksheets:

[chaseassaker]

This man, by himself, teaches me physics, chemistry, and calculus; all better than any of my professors. Honestly I'm so grateful to have you as a recourse JG! you have no idea how much it helps

[angkorgo]

Absolutely wonderful! I spent about two hours digging through dense textbooks with incomprehensible explanations - and all my professors were useless in describing the normal force when centripital forces were at play. Thanks so much!!!!

[estrellasirio]

Muchas gracias. Has explicado mejor que nadie el asunto de la mecánica de la montaña rusa. Enhorabuena. Soy profesor de Física y conozco muchas explicaciones de libros, cursos de universidades, etc.. y tu eres, sin duda, el que mejor lo hace. Estamos en deuda contigo, gracias desde Madrid.

[Il_Chigol]

Your physics videos made me understand every single thing way more better than any of my uni's teachers. I'm so grateful. Please go on!

[isabellaholland]

Thank you so much for this video, I have watched a few times to properly understand what I'm doing, but it was a real help in solving some (what now seem) simple problems!!! I love your videos so much, they really are beneficial!!

[sphystius]

Sometimes the simplest things mean the most, I really appreciate your help. Thank you.🧡

[davidkelly]

Thanks so much for this. My applied maths teacher didnt explain that you should think of the centripetal force as the resultant and I got it from your diagrams within the first 2 minutes

[BigPosay]

DADDYYYY YOU ATE THHAT I FINALLY UNDERSTAND WHAT IT MEANS WHEN NORMALCONTACT FORCE= 0 PAPI I LOVE YOU

[Aristothink]

You covered many parts here. Great video. Our educational system needs more high quality videos like yours.

[torphedo]

12:00 Thanks, I had the weight force sign backwards. I thought the centripetal force didn't include the weight and I needed to account for it by adding it to the normal force.

[SSN]

you are always thanking us for watching, but it should be the other way around, so thank you so much for every video🤜

[aanyajain]

Thankyou very much sir .I used to be so much confused in this topic but now it's crystal clear

[masoud]

Im gonna watch all of em. So well explained

[Patrick-kyez]

This man single handedly saves my every Physics grade

[JZFeser]

Thank you for saving me! Physics final tomorrow!

[totetoteable]

2022 and still it great video, man you explained so well the centripedal normal force, lovu

[fizixx]

In the first example you have "mg" as positive at position A, and at position B you have "-mg" but they both point in the same direction.

[dudeisawesome]

Thanks dude!! The 2nd problem really helped me understand about the required speed!!

[allisonbenjamin]

Great review for the AP Physics 1 exam, thank you!

[brenda]

I FUCKING LOVE U, MAN. I WAS STRUGGLING WITH THIS TOPIC ON IB PHYSIC AND NOW I UNDERSTOOD. THANK YOU MUCH