Stoichiometry of a Reaction in Solution

Stoichiometry of a Reaction in Solution

[SuperJbob]

you have no idea how much you're affecting my AP Chem grade right now. God Bless you

[MarciaArleneDebra]

One thing I can give credit to Khan for is honing in on the aspects of a problem that students will most likely not understand. As that hurdle is passed a light goes on. Understood! The key in learning is being aware of your impediments, and Sal always hits the nail on its head.

[AllieM]

This guy's voice reminds me of John Green. These videos help me so much. Not only do I understand these videos much more than my chem lecture class, but the John Green voice keeps me entertained. All the points to Khan Academy.

[carnaticmusiclover]

Thank you so much, you have a guaranteed place in heaven.

[saywat]

YOU MADE MY LIFE SO MUCH BETTER THANK YOU

[TheRoadsidePicnic]

And verily, it is written I went to explore each field of new knowledge and Sal Khan was there shining his light!

[elbay]

Well done; you're explaining this at the right speed. Ten minutes is excellent.

One comment: when multiplying by 100, you might want to remind the students of the effect that has on the decimal point instead of immediately going to the calculator (perhaps you were short on time..). Also - and this is a bit more advanced - before any calculation it might be a good idea to discuss what to expect in terms of the order of magnitude of the answer, as in the calculation at 6:08.

Cheers!

[lexsanz]

Chemistry Final Tomorrow - Thanks for the Help!! : )

[mahmoudgamal]

احسن حاجة الترجمة دي بتفدنا جدا استمرو

[sccm]

I honestly haven't found Khan Academy helpful in chemistry. Videos from 2006 are so much faster and explanatory.

[valschuck]

great job, i really need help in chemistry
Finals on monday!! :(
im dead!!

[maxaragon]

Easier: 25 ml HCL x (0.750 mol HCL / 1000 ml) x (1 mol CaCO3 / 2 mol HCL) x (100g CaCO3 / 1 mol CaCO3) = 0.937 g CaCO3

[AJ-mioc]

Thank you. It's very nicely explained.

[VipulVermavs]

The game is of my concentration my You like these that's why you concentrate more hence more understanding :D

[Apo]

OH MY GOD !!! Thank you much
This is a much better explanation than the one given by my teacher
thx

[tttuu]

Is why I like this guy he help m always!

[KayleighWayleigh]

There is a way that is so much easier. We want to find mol of 2HCl so n=c(concentration)x v(volume)=0.01875 the molar mad of caco3 =100.09g/mol mass=n(mol) x M(molar mass) =1.877

[TheToxicMegacolon]

I understand you want to break it down to the simplest but you should also do the much faster way lol
Regardless good video!

[martangeloilagan]

There's a much easier way to do it, you just made it longer.

[kutecurse]

if u use the formula and substitute the values..it would be much easier to understand..