Mechanics of Materials: Lesson 46 - Tough Combined Load Example Problem

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Mr. Hanson dripped out w the polo 💧💧I rate it

smohke
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Would not have snagged a B in solid mechanics without you !!

sagemerson
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Love it. Wish my proffs were half as good as you... Everything's just always clear with you for some reason, maybe i just have anxiety in class..

CaptainJuiccy
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Praying for this guy to hit the transfer portal. 5 star talent, years of on the field experience. Would be an amazing grab for any program.

andrewhodges
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at 8:41 how did he know which direction is the bending moment is? isnt it suppose to be to right because I assume follow the direction of the moment toward the centre of the gear?

damhilmn
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Great hardworking teacher, big respect

jawwadshigri
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thank you for helping me cram. 30 minutes til my exam and I finally get how it works!

nateracing
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Your lectures are great sir. Thanks for all your efforts

CivilThinking
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The B element is wrong because no shear stress can be created along x direction. So change the x direction to z direction and arrow for shear must be to the right at the top!

batuhandasdelen
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At 25:25 I'm having trouble understanding how to chose which direction to put the sigma stresses. "Stress element A" makes sense to me, the stress element is along the x-y plane and the combined stress is in the y direction so sigma_x=0. But it looks to me that "stress element B" is in the z-y plane so technically Mr. Hanson is right putting the 7.8ksi stress in the y-direction, but shouldn't it be drawn so that sigma_z=0 (not sigma_x=0)?

RandomCrap
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Wonderful solids lessons!! really taking the time to explain the problems along with a good sense of humor :))

manuboker
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Hello Mr. Hanson! Thank you for your great videos!
I have a question regarding the arrow direction. (Min 26.18 )On the top left you said that the middle square is our stress element and drew an arrow up on the left side and an arrow down on the right side. But on the actual stress element on the right of the board you did the left arrow pointing down and the right arrow pointing up. Can you please explain this?

Thanks !
Daniel

bloodyred
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Does the torsion not cause the A element Tau to be reversed cause its negative, why do you only consider the shear part of the value?

lolzaloud
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how would you find sigma x if you had compression or tension there. you only had sigma y which is confusing

XerathMTA
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Dr Hanson I got confused a little bit. Personally, when it comes to the shear stress, I'm taking a convention so clockwise negative and ccw positive because what confused me is that the torsional moment is positive for B and negative for A which isn't logical, the torsional moment rotates A and B in the same direction. So to conclude, the only difference is that I get the same stress components for both A and B (I don't know if this is supposed to happen). Please anyone who has really grasped my POV, I would appreciate if you could explain what is really happening.

antoups
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keşke son 4 chapteri son 2 güne ıbrakmasaydım

suleyman
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why is all of the stress sigma y and sigma x is zero

jameshume
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Lol my professor used this exact question for my midterm exam past few weeks, wish u uploaded sooner 🥹🥹🥹

johnsonpau