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Going from superheated to sub-cooled fluid | First Law | Thermodynamics
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Welcome to Engineering Hack! In today's video we are solving a Thermodynamic's closed system problem. We have R-134a on a cylinder device and that is going to a higher state of energy to a low state of energy, and we want to determine the amount of heat loss and show the process on a T-v diagram. The problem requires you to know the first law of thermodynamic that tell us that the change of internal energy will be the combination of the heat and the work being done by the system or to the system, also some other pure properties, such as the enthalpy is defined as the internal energy plus delta PV, witch we have seen on previously videos. Everything else comes by analyzing the problem and the system at hand.
Problem statement: A piston-cylinder device contains 5 kg of refrigerant R-134a at 800 kPa and 70°C. The refrigerant is now cooled at constant pressure until it exists as a liquid at 15°C. Determine the amount of heat loss and show the process on a T-v diagram with respect to saturation lines.
Answer:
a) 1172,85 kJ
b) T-v diagram (16:53)
R134a:
In this video:
00:00 Intro
00:37 Problem statement
01:04 Problem analysis
07:50 Defining first state
09:40 Defining second state
09:49 Ideal gas table
13:45 Difference in enthalpy
15:38 Heat loss
16:53 T-v diagram
18:27 Final Thoughts
🎓 Can you trust the answers and solutions provided? Well, you never should trust anything 100%. Make sure you are checking for yourself. When I’m solving the questions, I always solve on my own and then check the results against other sources. If there is divergence, I look for more sources. So while I can’t promise you everything will be 100% correct, I can promise I’ve done my due diligence before posting. If you enjoyed this video, please press the bell 🔔, like 👍, comment or share. You're the best, thanks!
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#Engineeringuniversity #problemsolving #EngineeringHack #engineeringsolutions #engineeringaustralia #engineering #university#propertytables #steamtables
Problem statement: A piston-cylinder device contains 5 kg of refrigerant R-134a at 800 kPa and 70°C. The refrigerant is now cooled at constant pressure until it exists as a liquid at 15°C. Determine the amount of heat loss and show the process on a T-v diagram with respect to saturation lines.
Answer:
a) 1172,85 kJ
b) T-v diagram (16:53)
R134a:
In this video:
00:00 Intro
00:37 Problem statement
01:04 Problem analysis
07:50 Defining first state
09:40 Defining second state
09:49 Ideal gas table
13:45 Difference in enthalpy
15:38 Heat loss
16:53 T-v diagram
18:27 Final Thoughts
🎓 Can you trust the answers and solutions provided? Well, you never should trust anything 100%. Make sure you are checking for yourself. When I’m solving the questions, I always solve on my own and then check the results against other sources. If there is divergence, I look for more sources. So while I can’t promise you everything will be 100% correct, I can promise I’ve done my due diligence before posting. If you enjoyed this video, please press the bell 🔔, like 👍, comment or share. You're the best, thanks!
----------------------------------------------------------------------------------------------------------------------- 🎥Watch More Videos:
#Engineeringuniversity #problemsolving #EngineeringHack #engineeringsolutions #engineeringaustralia #engineering #university#propertytables #steamtables
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