Calculus Derivatives (Hyperbolic Trig Functions): csch(x).

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csch(x) is simply 1/sinh(x).

We then need to apply the chain rule since we're dealing with a function composition.

We then perform the final derivative.

cosh(x)/sinh(x) is simply coth(x).

Since 1/sinh(x) = csch(x), we have our final simplified expression.

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