A tricky derivative using the limit definition #calculus

preview_player
Показать описание
🌟Support the channel🌟

🌟my other channels🌟

🌟My Links🌟

🌟How I make Thumbnails🌟

🌟Suggest a problem🌟
Рекомендации по теме
Комментарии
Автор

You can also do it by writing the fractional powers as 4th roots and rationalizing the numerator(then simplifying)

matheusjahnke
Автор

Just curious, anyone else on their math journey (self-study) get a bit intimidated by seeing so many shorts on different topics? It's like a constant reminder of different directions to go in and how little you know. I am not complaining about it but just curious do others learning math get a bit overwhelmed when just browsing along?

callmedeno
Автор

thought this was first principle at first cuz it looked similar

urnoob
Автор

If x->a, then a->x, too ye? So the end you should interchange the a with x

darcash
Автор

Gives us another reason to appericate the pwr rule

alis
Автор

Thank you for ahowing these! I really appreciate it and they help a lot! Please keep doung them 😊

jontedeakin
Автор

Let's not do that again I already passed that class please stop make it stop please aauughh

Joedex
Автор

you can simply just do the definition of derivative limit on x^a, find out that it always results in ax^(a-1) and then apply that to this question

gdmathguy
Автор

Cancel with the numerator at Uncle Chuck’s Cabin Rental

anyabureau
Автор

goes from english to mathenese real quick

devonpulley
Автор

That mine as well be chicken scratch to me

slamfire