Solving A Nonstandard Equation in Two Ways

preview_player
Показать описание
🤩 Hello everyone, I'm very excited to bring you a new channel (aplusbi)
Enjoy...and thank you for your support!!! 🧡🥰🎉🥳🧡

If you need to post a picture of your solution or idea:
#exponentialequations #algebra #logarithms
via @YouTube @Apple @Desmos @NotabilityApp @googledocs @canva

PLAYLISTS 🎵 :

Рекомендации по теме
Комментарии
Автор

There are complex solutions obtained by "complexifying" the RHS: sqrt(2) * x^(xqrt(2) ) * exp( sqrt(2) * x^(xqrt(2) ) ) = sqrt(2) * exp(sqrt(2) ) * exp( 2 pi i n )
Then apply LambertW to both sides. Only main branch of W yields solutions.

rah
Автор

Have you ever done a video on 4 - 4/3 + 4/5 - 4/7 + 4/9 - 4/11 + ... ? It's a well-known series but I'd be interested in learning your favorite methods for finding the sum.

Qermaq
Автор

Let f(x) = x^sqrt(2) +lnx -1. We’re looking for all roots of f.

f is only defined for x>0. Since f’(x) = sqrt(2)x^(sqrt(2)-1) + 1/x, f’(x) > 0 for all x>0. So f is strictly increasing and thus can have no more than one root.

By inspection, x=1 is a root. So x=1.

seanfraser
Автор

This one looks trickier than it is. Once I noticed 1 is a solution, it made me think of domains. x cannot be negative or else the equation makes no real sense. As x goes from 1 toward 0 ln(x) decreases faster than pi/4, and as it goes up it levels out. But taking a number to a power greater than 1 does kinda the opposite. It leaves the neighborhood of 0 fairly level and the slope gets steeper. So because the lines are curved opposite to one another you won't get another intersection.

Qermaq
Автор

I just guessed and checked by plugging in x=1.

scottleung
Автор

I am getting used to these! Solved it with a bit of manipulation.

mcwulf
Автор

Gracias profesor por el tiempo que nos dedica y espero que tenga una feliz navidad en compañía de sus seres queridos.

bramont