Calculus 2: Applications - Calculating Work (13 of 16) Cal. Work Ex. 12: 1/2-Spherical Tank: 1

In this video I will calculate W=? of pumping all the water out of a semi-spherical tank, part 1.

Next video in the series can be seen at:

[ptyptypty]

WHOA!! Guess what, Michel ??.. I tried your other method of finding work by concentrating all the mass at the CENTER OF MASS of a Hemisphere and then lifting it up... Center of Mass = (3/8) R .. and the distance to lift it is (5/8) R ... and since I'm using HALF the volume of a sphere I insert the (1/2) factor in the equation.. I won't write it out here, but... IT WORKS !!! :) As usual, THANKS for your Patented Method of Explaining and demonstrating!! (by the way, I found the Center of Mass for a Hemisphere from one of your other videos!!)

[osvaldodossantos]

Some sites have shown half sphere inverted with the same radium value. However the final result is different. Same exercise just inverted. Why the final result is different?

[ptyptypty]

Let me see how that amount of work compares to me. If my mass is equal to 100 kg, my weight is 100 x 9.8 = 980 N... How high would I have to climb a vertical ladder straight up to equal 8.02 E 6 Joules?... that would be 8.02E6 J / 980 N = 8.18 km !! WOW... that's alot of work! (didn't even break a sweat!) :D Cool Video Michel... do people still use the word, "Cool?" :D

[ahmedal-ebrashy]

Sir, why the dw is equal 5-y and not just R ?