Find the derivative implicitly. #calculus

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Finally something from Michael I know how to do 😂

luker.
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Thanx. Nice and straight to the point. I'm a geometer and I love symmetry. The gradient is (6x^2 - 9y, 6y^2 - 9x). @ (2, 1) this is (15, -12), the perp. is (12, 15). So the tangent is (2 + 12t, 1 + 15 t), or y = 5/4 x - 3/2 if one prefers y =f(x).

biodreg
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This is actually a very special curve called the "Folium of Descartes", x³ + y³ = 3axy. It has a tangent and normal at the same point which is (0, 0)

math_Nerd-ntgb
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This was awesome, as Implicit differentiation leads to partial derivatives.

marcuswesley
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Oh sweet existential horrors beyond my understamding

Furry-iousNews
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Using the substitution y = tx, this curve parametrizes as (x, y) = ( 9t / 2t^3+2, 9t^2 / 2t^3+2 ). :)

davidblauyoutube
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Really? I don't recall ever being taught this. Would it work for finding the tangent plane in R3?

keithmasumoto
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better use partial differentiation formula for implicit functions

varun
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I love math but in the words of the great Big Z from surfs up "No joy man, No joy"

jacobneal
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I didn't even understand the world used to create the question that you used to solve the thing no one asked lol but God job

mktrill