HCV: A person standing near the edge of the top of a building throws two balls A and B. The ball A

preview_player
Показать описание
A person standing near the edge of the top of a building throws two balls A and B. The ball A is thrown vertically upward and B is thrown vertically downward with the same speed. The ball A hits the ground with a speed vA and the ball B hits the ground with a speed vB. We have

Solutions to HCV Class XI Rest & Motion Kinematics | JEE NEET Physics | Doubt Counter

#JEEMains
#JEEAdvanced
#IITJEEPhysicsLectures
#JEE
#JEEMainsPreparation
#IITJEE
#JEEExam
#IITJEEMains
#JEEMainsExam
#IITPhysics
#JEEPhysics
#IITJEEPhysics
#JEEPreparation
#IITExam
#IITMains
#IITPreparation
#PhysicsJEEMains
#IITJEEPreparation
#JEEMainPhysics
#IITJEEExam
#IITLectures
#BestCoachingForIIT
#OnlineCoachingForIITJEE
#LearnLiveOnline
#OnlineJEECoaching
#OnlineClasses
#howtocrackJEE
#strategy
#NEET
#NEETpreparation
#NEETPhysics
#NEETExam
#NEETLectures
#NEETPhysicsLectures
Рекомендации по теме
Комментарии
Автор

Sir ...jab ball "a" ko upar fekenge to height to increase ho jaaygi ....aur fir free fall wali equation se option (a) correct ho jaayga?

mayurpal