Check Continuity of Function at Given Point

CORRECTION : x^3 + 27 = (x + 3)(x^2 - 3x + 9) and not as given in my solution.
However, the answer remains, Hole at x = -3 the function is discontinuous at x = -3.
Thanks to my Subscriber for pointing that out.
Highly appreciate it.

[Et_sapien]

It is very helpful. thank you teacher !

[shihanjanith]

Expand of (x^3 +27) must be (x+3) (x^2+3x+9)

[MathKnows]

thanks for this video. it really help me a lot.

[biswanathbera]

First factorisation is wrong. X^3+27= (x++3) (x^2-3x+9) .

[IrfanAli-xvvm]

Sir we can't put -3 in second statement of peacewise function

[omnibrain]

The first question is continuous at 1/25 sir.The denominator factorization is (x+3)(x^2-3x+9).What do you think, sir?

[crazyjester]

Sir, a question why did you plug -3 in the last question even though strictly state you are supposed to plug x<3.

[njumewazacky]

You are too slow, you spend much time explaining nothing