Find all possible values of X | Triangle Inequality Theorem | Important math skills explained

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Find all possible values of X | Triangle Inequality Theorem | Important math skills explained

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Find all possible values of X

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Case 4: *all side must be positif*
b & c are fine, but 'a' > 0
4x - 5 > 0 ➡ x > 5/4
Luckily x > 5/3 is above 5/4. 😉

rudychan
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Another limit is that x > 5/4. If not, side BC would go negative. However, the x > 5/3 limit overrides this.

allanflippin
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Let me make it clear that I love your teaching love your voice and love your channel ... I am a math teacher who love learning new ways to teach math

uniquetalentinjamaican
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Love this one, logical rather than mathematical, interesting the inequalities give results.. very interesting, never knew this, thanks for filling in the gaps.... In my head 😃👍🏻

theoyanto
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I wanna add that obviously all sides must be of positive value, so x>-3/2, x>-3, x>5/4 must all be fulfilled too.
But 5/3 is bigger than all of them, so this is redundant.

rafaelliman
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Nicely done. I workred differently. I assigned values to x and went with trial and error (improvement). I got the <11. I went wrong somewhere at the other end but see where I went wrong now.

MrPaulc
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Good question and good solution. Depiction is superb !

gopalsamykannan
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Welcome to you tube world ❤️🙏 sir always milestone presentation ❤️🙏🙏🙏great greetings from India ❤️🙏🙏🙏

zplusacademy
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Once you had x>5/3, the x>1 was a non-factor is solving this.

BigfistJP
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I thought about using Heron's formula, but I don't think it is necessary. If x = 5/3 then the 3 side lengths are 19/3, 14/3 and 5/3. x must be larger than 5/3 and if it is larger then each of the sides is larger and hence the area is larger. So Heron's formula won't give any values of x that further restrict the possible values of x. What do you reckon?

RexBoggs
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Can you tell me what software you are using ? This software works very well to draw any contents when you are talking.

weiweiwang
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What about saying that a side of the triangle must be greater than the difference of the other two and lower than the sum of the other two and examinating only one case?

matteovolonghi
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By using Heron's formula, it turns out that side b is the height. So this is actually a right triangle, where a^2+b^2=c^2. The solution is then x=(23+2*sqrt(51))/13. I didn't consider x=(23-2*sqrt(51))/13 a solution since it's less than 1. BTW, I thought it a bit strange that side b (x+3) looks longer than side c (2x+3).

barbazzo
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3x+6>4x-5=>x<11 , x>,11 > x>1

adgfx
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How do you tell which one is a b or c?

gabetheminerofficial
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What about plugging the values into Heron's formula?

tompeled
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Hello sir how can i send you more questions?

yashveersingh
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Possible values of x are greater than equal 1and less than 11.

adgfx
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Its so sad that I was never exposed to this theorem... I would almost believe that this is not possible

uniquetalentinjamaican
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Hi sir I try to solve it.. What is your real name.. Sir

NITINCHAUHA