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Orbital Overlap Diagram for C2H4 (Ethene / acetylene, double bond)
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Ethene, which is two carbon atoms double bonded and two hydrogen atoms on EACH carbon (four hydrogen atoms total), requires ONE pi bond. This means each carbon is sp2 hybridized. This in turn means you have three hybridized sp2 orbitals arranged in a trigonal-planar way around each carbon, AND you have a leftover p orbital on each as well. You can show the overlap of these orbitals to make sigma and pi bonds.
Orbital Overlap Diagram for C2H4 (Ethene / acetylene, double bond)
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