Relative Motion | Motion in 1-D for JEE & NEET | Class 11 #OnionPhysics | Mechanics L-7

Relative Motion in one dimension covered extensively in Onion Physics Lecture-7 for JEE and NEET. In this online physics lecture of motion in one dimension, Ashish Arora sir has covered fundamental concepts of relative motion between bodies that will help students to build fundamental understanding of solving numerical problems of relative motion. In kinematics, relative motion is one of the most important tool to solve questions of rectilinear motion of two bodies which are frequently asked in JEE Main, JEE Advanced and NEET exams. In the onion physics series, this lecture is focused on different cases of relative motion in one dimension analyzed by various illustrations and physical situation applications.

The best method to learn how to solve numerical problems of kinematics and rectilinear motion is to start building application-based understanding with different physical situations. Learning through illustrations is one of the best problem-solving approach. Kinematics of one dimension and motion in a straight line forms the basis of understanding the fundamental mechanics of class 11.

Onion Physics is a FREE You Tube series for High Quality Online Physics Classes for JEE & NEET preparation. In this series, complete physics is taught through Illustrations based on different physical situations. JEE Main and NEET are competitive exams in which about 50 percent of questions are based on applications of physical situations and the rest are based on memory and fundamental analytical concepts. In JEE Advanced all questions asked are purely on applications of concepts in simple as well as complex experiments and physical situations. Onion Physics is focused on learning through examples and different physical situations which makes it the best online jee coaching available in Physics.

#rigidbodydynamics #rotationalmotion #jeemain #jeeadvanced #neet #jeepreparation #neetpreparation #onionphysics

[xordp]

30:00 The answer to the question related to the two cars trying to avoid accident is that, the traditional method is correct. When using relative motion concept, it doesn't take into account the time when the car A is stopped. Yes it retards, but the question specifically says retardation due to braking, and braking doesn't reverse the car's direction. So relative acceleration changes after it comes to rest because after that its not retarding anymore.
Hence traditional method is correct
Correct me if i'm wrong, Thank you

[deveshkhamayacha]

30:11 S3 Two cars avoiding cases : 5m/s^2 is correct ans.
Because when 4m/s^2 is taken it means car b covers 200m distance before coming to rest which is impossible in this case as both cars are approaching.
Hence with traditional method 5m/s^2 is correct...

[satyampandeyII]

Literally IDK how will anyone get distracted by anything if they have this wonderful webseries to watch.

[siddhantshastri]

@physics galaxy 22:30 Sa = 20t + t^2
Sb =40t
explanation:
Now, let at time t=t1 A overtakes B
distance travelled by b= S1
" " " a=200+S1
therefore Sa-Sb = 200
t^2 -20t =200

[brahmachariinsaan]

No advertising, no faltu discussion, only jee and neet preparation:Ashish Arora sir❤️❤️❤️

[itsme-tjtr]

When sir says - "pogi clr
I was like pogiii rukkkooo 😅 note to kr lene do 😬😬😂😂😂

[manjulatasuman]

GREAT TEACHER, MENTER,ALSO HEALTH CARING PERSON

[TheAditya-ztpb]

This is Mind blowing lecture, I can feel like i am going deep inside the concept and understanding it to the fullest

[kritharthbaishnab]

as best of my knowledge, answer doesn't matched because:
in traditional method we can easily find that their time of stopping is not same it just implies that one of the car will stop earlier and it will have to wait for another car to stop just in front of it,
while solving it through relative we got different acceleration because in this case both car will stop in same time and their is no need for one of the car to wait for another.
sir you are like a god for me, i stucked in this question 2years ago and everytime i used to think about it but never have thought that you are going to take this concept in your next lecture, thank you so much sir

[harshkhandagale]

Thank you sir! The concepts were beautifully explained.

[digantadhara]

Sir, I would like to thank u for a thing as I fell ill when in my coaching centre I had to start my prep for IIT JEE 2023. I had a lot of backlog as teachers had completed till NLM but I had not started anything in PHYSICS. Your recorded lectures on the Physics Galaxy helped me to cover it efficiently. Now I think I have gained a lot of confidence . Sir extremely thank you from the core of my heart for your wonderful illustrative lectures...🙂🙂

[sushilsharma]

Now I know why Allen is best aisa teacher aaj tak nhi dekha bhai sahab op sir

[devangsharma]

30:00 sir mere according car ek dusre ko cross krke firr again cross kri. As we know in relative motion we deal with vector quantity therefore it is incorrect. But in traditional method we indirectly use displacement as distance therefore it make our desire situation correct.

[Gaurav-llcb]

30:11 where can I find the reason/solution?Pls mention lec where sir discussed this!
Is it related with inertial/non inertial frame?

[artisticnoob]

me : physics is tough
ashish sir : hold my pogi

[swetamona]

S-3=to avoid collision, acceleration of B should be greater than or equals to 5m/s^2( reason- distance travelled by A having retardation 5m/s^2=40m and distance travelled by B with retardation 5m/s^2= 160m. Total distance b/w them is 200m.But if retardation of B is less than 5, then distance travelled by it would be greater than 160m)

[wantbebigcoder]

My first teacher who help me understanding physics

[shivanshusingh]

Sir in traditional method we have not considered the simultaneous time condition that when a will reach 100 then b will also
When we chech by calculation we find that they take different timesto reach 100 m
Whereas the simultaneous time condition has been considered in relativel concept
Thankyou

[kishangodedara]

Sir, we have considered any one of the body to find relative acceleration so then this reference frame is an accelerated frame of reference. And equations of motion does not apply (an drawback of equations of motion) to accelerated motion so we get a wrong answer as 4 m/s2.---Kishan g odedara

[maninair]

Sir, after doing the relative motion's confusing problem, I verified the calculations of both methods, the traditional method satisfies the total distance value of 200 m, but the alternative one gives us value about 240 m. Hence, traditional method is correct.