A Quick and Easy Functional Equation

#Shorts #algebra #equations #multiplication #maths #math #mathematics #puzzles #via @YouTube @Apple @Desmos @NotabilityApp @googledocs @canva

[dbmalesani]

I think this proof would still leave the possibility open that f(1) = f₁ ≠ 0.

But then, setting x = y = 1, we get 0 = f(2) = 2·f(1) = 2f₁, hence f₁ = 0.

[Iamnotyou]

f'(x)=lim h→0 (f(x+h)-f(x))/h
=f(x) lim h→0 (x+h-1)/h
from here we can also conclude f(x)=0

[stopworryingstartliving]

Try questionsfrom rmo or inmo olympiads in india

[dakshhooda]

Can't we take y=x and then solve the functional eqn it would give f(x)=2x

[AileenyElynaGloRiu]

Could'nt understand a half of what you said but cute voice 👍