Implicit differentiation, product and chain rules at once

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Implicit differentiation, product and chain rules at once
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What about just using the chain rule right off the bat? x(ln(x))^(x-1) * (1/x)
If I haven't made an error - then isn't that far simpler?

billyshakes-tg
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Always good to review those logarithmic properties, very useful in Calc.!

TheCaptain
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This is the first video I've seen that hints at you using the program ArtRage

necrolord
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Thank you, Sal! It truly means a lot!

PureLiquidLuck
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What about converting ln(x) into e^ln(ln(x)), which seems simplified the whole process  lol

yuyuzhang