Figure (9-E11) shows a small block of mass m which is started with a speed v on the horizontal part

Figure (9-E11) shows a small block of mass m which is
started with a speed v on the horizontal part of the
bigger block of mass M placed on a horizontal floor. The
curved part of the surface shown is semicircular. All the
surfaces are frictionless. Find the speed of the bigger
block when the smaller block reaches the point A of the
surface
Welcome to Physics With Shubham

you can discuss your doubts with me here:

Lets join hands to learn together!!
#JEEMains​
#JEEAdvanced
#NEET
#JEE
#IIT
#PhysicsWithShubham

[spaceboy]

sir maine toh mv=MV+mv kar diya tha kyoki agar system maan luu toh block or wedge ke normal internal ho jaayega or jub block upar chadna chalu karega toh block ke normalsintheta ke karar block move karna chalu ho jaayega or system maan liya tha toh us smay block ki velocity ho jaayegi

[harshitagrawal]

At 60 degree the value of Vm is coming:
√{[v^2×(4m-1)]÷4[m^2 -1 -√3m+M]}
It was very tough to solve this. I might have got something wrong. Please check this.
And yes the video was very good.

[jatinsingh-yzrz]

sir plz reply ki block with MASS M will not recoil back???kyunki law of conservation of momentum ke hisab se toh

[supersomething]

When the body with mass m moves on the horizontal part wouldn't the bigger block of mass M recoil backward first with some velocity?

[HarshitSharma-gkkc]

For conservation of energy won’t radius as a variable increase ?

[vikassuryawanshi]

How can we conserve momentum if Gravity acts as external force

[GauravRaj-hd]

Bhaiya mera negative aa rha, or logically negative hi Aana chahie, Kyunki u velocity to negative direction me hoga n, small
m ke liye

[RyanO]

Bro you are in which class or in any college or iit

[invinciblegamer]

Sir if we think that initially small m had vel=v in x directions and then at pt A it's velocity is in y direction
So if we conserve momentum in x direction then mv=M(v')
Then v'=mv/M...please tell where am I mistaken