AQA Core 4 6.02 Introducing Implicit Differentiation

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its the night before the exam at half 12 and this has really helped, thanks dude

eddiefitzpatrick
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In 4 mins you explained something so clearly and precisely that my teacher failed to teach me in 3 lessons, thank you.

Craziestbanana
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watching your whole C4 playlist at speed of ×2 a day before my exam ;)

samiulhussain
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You could also use the chain rule on y^3

zaainnn
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Actually no worries Jack. Im guessing you differentiated it into 1 but then you must stick a "dy/dx" after it so 1(dy/dx)=dy/dx. Correct me if im wrong.

Legenddeadmanever
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Why do you differentiate "y" into "dy/dx" insted of into "1"? And plus why were you differentiating y^3 using the product rule when you could simply bring the power down and minus one from the power?

Legenddeadmanever
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Hey I’m from Scotland and I was wondering if this would be the first or second year of a level

Paul-obhy
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Hi Jack,
How come when you differentiated ysin(x), you didn't times the whole ycos(x) + sin(x) by dy/dx and only the sin(x) part?

huthaifaahmed
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Wouldn't the numerator of the final answer be - 3x^2 - ycosx instead of the (+) ?

israrahmed