Mechanics of Materials: Lesson 12 - Strain Energy; Example Problems From Stress Strain Diagram

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Dr. Hanson using his powers of Statics, Dynamics and Strengths to levitate that broom with his mind, Truly a legendary man.

nastynork
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hey so I just wanted to say thank you becuse you helped me so much in this midterm season. I was working so I couldnt go to the courses and I found you in youtube and you made my life so much easier. 2 days after I have the mechanics of materials midterm and I was never confident about myself in this course before you. thank you very much

ikaros_
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U (resilience) = Area untill proportional limit (MPa)
U (toughness) = Area untill fracture point (MPa)
Energy absorbed = U x Volume (J)

KIMIRAIKKONEN
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Welcome back professor Hanson !! Pleasure to see you live again. Lots of best wishes from Alberta, Canada !!!!

RK-txxb
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My solution for Number 9 is as follows.
The total deformation when the rod is loaded: 0.003 + (701.7-600)/(780-600) * (0.005 - 0.003) = 4.13e-3 mm/mm.
The deformation that is removed when the rod is unloaded: (701.7 MPa)/(2e5 MPa) = 3.508e-3 mm/mm.
The permanent deformation is 4.13e-3 - 3.508e-3 = 6.22e-4 mm/mm or delta = 6.22e-4 * 600 mm = 0.3732 mm.

sgpark
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First!!! I have never been happier to see you So much love from Canada

Fahimsyd
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İ love you Hanson sensei, Even the way you talk puts me at ease. I'm getting away from my worries. Thank you I'm glad I met you, I'm glad you exist. (from a civil engineering student, Turkey)

herseyodtuyeyataygecisyapm
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Yes! I’m currently taking it. Thanks for this.

reyjr
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25:50 Poisson's ratio is not always positive. There are negative cases, which exhibit the behavior expected from a negative value.

usandmexico
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Shouldn't number 8's answer be 241.75 N.m?

scottybarra
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doctor hanson you are freaking awesome

aramhadizadeh
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i wish you have other engineering classes on thank you jeff hanson

aslsahdemirtas
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Hi, thank you for the excellent video. I am trying to calculate the compaction energy when compressing soil. I have a stress / strain curve for this and have followed the same approach detailed in the video. So that I can compare compaction energy with samples of different size, how do I calculate energy density per m3 of material?

TruePreView
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In the 4th section, isnt the max tensile stress before fracture supposed to be 780MPa, as it is the UTS

epicfailled
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I hope that if Jeff has kids, his dad is the coolest person ever

NexiOHome
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I have an exam in 2 days for solids any tips?

Edit: I GOT 95 FOR THE UNIT
Thanks Jeff Hanson

tblol
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Prof. why you didn't choose the sigma ultimate as max load that the rod can handle before failure? Well, after the ultimate load, the specimen will start to let go itself before the force on it, then practically, the max load that the rod sustain before fracture is the max load sigma ultimate after that, the material won't sustain any load anymore, it just suspended like that. Isn't it?

A.Hisham
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Damet garm dr 😂 👌🏻👌🏻
Its a persian term means Well Done 👍🏻 ✌️

mohammadali
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Thank you Dr. Hanson.
I have one little obsrvation: I think for question 4 we should have taken the 780 MPa value. Am I right?
Because 450 MPa it is still under the yield strenth.

rogerdelbarco
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I am sorry but seems that there is a mistake about the strain engery density, after some unit deduction, you will find that (stress * strain)/2 is the density and the strain engery absorbed should be the density multiple the volume.

XinLiu-tg