Mechanics of Materials: Lesson 11 - Modulus of Elasticity Example Problem

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Dr. Hanson, you are an amazing teacher especially-especially for those who wants to know why instead of just the formulas. Thank you!

ozlemd.
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can we just find the strain of BC by using delta (.025) over original length (48'')

quangduongminh
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Thankyou very much for the video professor it really helped a lot, however I have a doubt: at 2:24 how did you know that rod AD rather than bending in a parabolic shape at point B, point D also had a displacement and whole rod AD went down?

MithilJha-ey
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When finding strain in DE, arent you supposed to divide the displacement .0417 by the full length of 60"? Not by length AB as shown. Please correct me if I'm wrong!

snorreleretpettersen
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Thank you for your videos professor! Are you using the Mechanics of Materials book by Goodno and Gere?

ishajak
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Sir, May I know what is the book name that you were showing to us?

aungyeoo
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When solving for the strain in BC why cant u just do 0.025/48 to find the strain?

likjjj
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What if you assume the beam is sagging.
Then, the change in D won't be 0.0417.

jaguirre
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When I divide the force 112 kips over area 0.002 in^2 I get 56000 ksi and the ksi goes away with modulus 29000 ksi to get unitless strain to be 1.93… I don’t understand how Jeff cuts it down to 56 for the stress BC, can someone explain pls 🙏

pabloarmijo