Mechanics of Materials: Lesson 18 - Axial Elongation Example Problem, Displacement

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The displacement for B is 0.03161+0.0016858=0.0332958, not 0.033468.

Darius-ustw
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Thank you for the great video! I believe the last calculation adds the displacement at E and the stretch of EB. It should be .0016858+.03161=.0332858, slightly different from video

bradvincent
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This is presented so beautifully, thank you so much! God bless you.

SS-pnss
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Thank you for this excellent explanation.
You're better than my college teacher.

fluniyg
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To find the Y which is the displacement of E. I think you forgot sir to convert the 8 ft and 2 ft to inches. Because the results of delta's EB and CF are in inches. But you've use 10' and 2' for the similar triangle.

dagsilryancristianp.bsee-
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Would the weight of the members be relevant in a real-world application or are they small enough that they are negligible?

drew
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Why are we adding displacement of e and the stretch of the member to find displacement of b? And what's the difference between the stretching of a member and a point?

Someone please respond quick. My exam is tomorrow😭😭

mwenge
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for calculation 12.5 mm radius should converted into inches 0.4921 inch= 12.5mm

amolsandbhor
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Isn't y the change in height of eb? so isnt it the same as δeb? why are the values for δeb and y different?

ashar
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Shouldn't the members FC & BE be in compression? Just a little confused on why they are stretching.

stevemaldonadomelendez