Proving weird Fermat's Last Theorem in just 2 minutes !

Changing the exponents in Fermat's Last theorem creates a whole new interesting problem. Do you need to be Andrew Wiles to solve it ?

#fermat
#manim
#Wiles

[mychannel-teke]

Oh, I think I had this question around 7 or 8 years ago on a math olympiad!

[chixenlegjo]

Yeah very simple problem. Got it in my 4th grade math test last year.

[tenebrae]

How does (x+1)*(x+1)^x become 2(x+1)^x at 1:37 ? Also, this is completely different problem than Fermat's Last theorem, isn't it?

[Phymacss]

**This video is too short to fit the proof**

[CarlBolton-rjyk]

Your assumption at the beginning is not clear. It doesn't explicitly state how n substitution by x, y, and z still holds for the original problem.

[xn____]

What about x^y+y^x=z^z? And for x^y+y^z=x^z?

[williejohnson]

Wrong again. This is the Beal conjecture. And just like I have proven the negation of Fermat's last theorem I have also provided a solution to this problem.
The key is to simply consider x, y, and z as exponents.

If we allow the integers A, B, C to represent the prime integers exponents 2, 3, 5, respectively and x, y, z to represent their integer powers 14, 4, 8, respectively then by the law of exponents [(14 x 2)+(4 x 3)=(5 x 8)]=[28+12=40]. And since A, B, and C are prime then they can have no common prime factor. Therefore the Beal conjecture is false.

Now. If you are saying that the base and exponent must have the same power then this is simply the Pythagorean theorem.

Therefore given the law of exponents
(3^3)+(4^4)=(5^5)
=(3x3) +(4x4)=(5x5)
=(3^2)+(4^2)=(5^2)
QED

[Kysil.A.G]

/from Ал-тай ДіЙ :/
Fermat's Great Theorem 1637 - 2016 !
I have proved on 09/14/2016 the ONLY POSSIBLE proof of the Great Fermat's Last Theorem .
I can pronounce the formula for the proof of Fermat's Great Theorem:
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5 - Fermat's Great Theorem proved in 2 pages of a notebook
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7 - the proof of the great Fermat's last theorem, as well as the formulation, is easy for a student of the 5th grade of the school to understand !!!
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