Why 82,000 is an extraordinary number - Numberphile

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NUMBERPHILE

Videos by Brady Haran

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2, 3, 4, 82000
Well that escalated quickly.

PauLtus_B
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I like this guy. He is so relentlessly enthusiastic about everything. :D

WereDictionary
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how do pure mathematicians sleep with these many mysteries floating around :D

SuperPeacebreaker
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What is the next number in this sequence?
2, 3, 4, ?

A)6
B)5
C)42
D)82, 000

georgesorkin
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Numberphile videos need a NSFW tag. It's hard to get any work done after watching them.

Jake-Day
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If we go on like this, all numbers will be special by the end of the year :P

MegaManki
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Came back to this because I parked my car and saw it was at 82, 000 miles

SatisfyingWhirlpools
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Number 45 is also special as it is the only number of its kind, no other number is 45. Same goes for 62892, 80085, and 3 among others.

Redheisenberg
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This video reminds me of a mathematical joke: "Why do mathematicians celebrate Christmas on Halloween?"
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.
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"Because Oct. 31 = Dec. 25"

santisica
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The thing I like most about James, and also everyone else associated with Numberphile, is that he doesn't seem to talk down to you as a viewer. Mathematicians are known for being condescending to people who aren't equally as or more intelligent than them. And that's why I like Numberphile so much. They actually apply their skills from the mathematical world and make it actually somewhat interesting and perhaps even fun. Keep it up guys! :)

seanathin-cn
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Really liked this video . Brought us back to the fundamentals of what makes numberphile videos fascinating . Also, can't ever go wrong with Dr. James Grime ; always contagious with his enthusiasm .

counting
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no one:
no one ever:
nobody ever in the universe:
numberphile: why is 82, 000 special?

felicityc
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As a computer scientist, it pained me to see you put binary digits in groups of 3

WastedMeerkat
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"Or is it?"
-Vsauce (michael here)

SnippingTool
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I love this guy, he is allways smilling

johnnightmare
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why do programmers often confuse halloween and christmas? oct 31 = dec 25

jimharmon
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Since they searched up to 2k digits, let's say they find another one that's 2000 digits. You'd expect its representation to be random digits in base 6 (or following Benford's law), so each digit has a 2/6 chance of being 0 or 1. Therefore, you'd expect to have to find 3^2000 numbers that work in base 5 before finding one that works in base 6 (about 10^1000). But the number of digits increases very quickly as well! If there are any real mathematicians here, it comes out to be E = p+p*sum(n=1 to inf, p^n*(n+1)*prod(m=1 to n, 1-p^m)) where p = 1/3^2000; find E to get expected # of digits for the next number.

electrollama
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Love it. Please post more videos about open problems. It's a part of math people don't generally get experience with in high school, but it make math seem so much more approachable I think.

Mathhead
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please do a video on fractional or irrational bases... base pi anyone?

FASTFASTmusic
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Watching your videos is soooo relaxing to me !! All problems out there seem gone for 5 minutes !!!

pol
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