Balance the Redox Reaction MnO4 - + SO3 2- → MnO2 + SO4 2- in Basic (and acidic) Medium

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To balance the redox reaction for MnO4 - + SO3 2- → MnO2 + SO4 2- in basic (and acidic) medium we’ll follow five basic steps (see below).

We'll start balancing as if we were in acidic medium and then add one last step at the end to convert to a basic medium/solution.

In this video I’ll walk you through the process for successfully balancing this reduction-oxidation reaction. We'll use the ion-electron method, also called the half-reaction method, to balance this reduction-oxidation reaction.

----Helpful Resources-----

----- Five Steps to Balance Redox Reactions ----
1) Write the oxidation numbers for each element.
2) Write the half reactions for the species of interest.
3) Balance each half-reactions for:
- atoms of interest.
- Oxygen (O) atoms by adding H2O.
- Hydrogen (H) atoms by adding H+ ions.
- electrons (charge) by adding electrons.
4) Balance the overall equation for electrons (charge).
5) Add half reactions and simplify.

Redox reactions, like MnO4 - + SO3 2- → MnO2 + SO4 2- in basic medium , are one of them most challenging topics in chemistry. They require careful attention to detail and a strong conceptual understanding of oxidation and reduction. To be successful:

- Check to make sure you have the equation written correctly.
- Get the oxidation numbers correct first!
- Take your time. Simple mistakes are easy to make.
- Think about what is happening and if it makes sense.
- Check your work. Are the number of atoms on each side equal? Does charge balance?

Finally, becoming proficient at balancing redox reactions requires lots and lots of practice. This is especially true because of the many steps and things to keep track of.

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xenonolegz
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The acetone has an oxygen that contains two pairs of none bonding electrons
But in the molecular geometry they don't consider it and I looked it up and saw that it was trigonal planar 120 degrees
What happened to the two lone pairs?? I need your help
Is it because it's a ketone so we remove the lone pairs to make it positively charged?

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