Redox Balance MnO4- + Br- = MnO2 + BrO3- || Oxidation Number Method

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This video explains redox balancing of reaction of permanganate ion with bromide ion in basic medium by Oxidation number method.
Steps to be followed

Step 1 – Assign oxidation number
Assign Oxidation number for Mn & Br. Oxidation number of Mn in MnO4- is +7 and in MnO2, its oxidation number is reduced to +4. This shows that permanganate ion is the Oxidant and Bromide ion is the reductant.

Step 2 –ION & DON
Segregate the reaction into ION( increase in Oxidation Number )& DON (Decrease in Oxidation number, Then do the following
1.Balance atoms other than Hydrogen& oxygen
2.Balance O.N
Once completing step 2, Rewrite the original redox reaction.

Step 3- Balance ionic charge by adding H+ for acidic medium & OH- for basic medium
As the reaction occurs in basic medium and the ionic charges are not equal on both sides add 2 OH- ions on the right to make ionic charges equal.

Step 4 – Balance Hydrogen atoms by adding H2O
To balance H- atoms, add 1 H2O molecule on the left side to get balanced redox change.

Step 5 – Check number of Oxygen atoms for final checking of answer

2MnO4-(aq) + Br-(aq) +H2O =2MnO2(s) + BrO3- (aq) + 2OH-(aq)
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Absolutely loved this explanation, thank you soo much for the help

asherthomas
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Thank you soo much ma'am ✨❤️
It was a very helpful

gang-seo-na
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Your channel is very useful for students
Nice sharing

KVsPlantsOrchids
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thank you mam but incase oxygen is not balanced then what should we add ??

or should it always be balanced or smth ??

rishitrawat
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Wow! It's so informative! Very well explained good job my friend! This is very useful! Thanks for sharing my friend! Done dear..

BalilingStrikes
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Amazing explanation dear.
Step by step teaching is very nice. Keep rocking.

chithoorssamayal
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well explain ..its very important for students ..

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