Complex Matrices

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MIT 18.06SC Linear Algebra, Fall 2011
Instructor: David Shirokoff

A teaching assistant works through a problem on complex matrices.

License: Creative Commons BY-NC-SA
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I thought Hermitian matrices have to have real values on the diagonal but that's not the case for S. The factorization still gives A on the multiplication but does it makes sense to change the order of the eigenvectors (and eigenvalues) to get real on diagonal?

RahulThakkar
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9:43, shouldn't the len of vector u be a square root of 1 + 2i, not a square root of 3?

АлександрСницаренко-рд
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why is the length of u = (1, 1+i) = 2? 9:43 isnt i a complex number? how does it become a 1 ?

quirkyquester
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I have a question. To normalize the matrix why did we take the length of one eigen vector and multiply it throughout the eigenvector matrix (to both eigenvectors). Both eigenvectors have different lengths so shouldn't there be a different length multiplication for the two different eigenvectors in order to normalize?

gauranggarg
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shouldn't the eigen vector for lambda=1 be [1+i -1] ?

DeepakSingh-xtio