Derivative of Sqrt (x) from first principles

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In this video , I showed how to differentiate square-root of x from first principles
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The first principle is to watch all the videos by Prime Newtons! ❤🎉😊

punditgi
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Wow, No one can explain it better than this, this guy does not skip even the obvious step….impressive, clear.

AliM-gftq
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You reminded me of this lesson when I was 17 years old. Now I am 60 years old. Thank you.

mustaphaballaji
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*_Never stop learning._* Advice I liked to give my own students. And when you master the understanding, you can more easily do word problems.

😎♥✝🇺🇸💯

RodMartinJr
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As soon as I saw you I just knew it was gonna be exactly what I needed. Cheers mate

lucas-nwn
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Once i learned the power rule, I never looked back. But this is so important to know...its how you solve complex stuff

brrrayday
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Along with the math, dispensing valuable life advice like "never touch the bottom"

richardbraakman
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How fabulous the presentation on the math question😊

JAMESYUN-et
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Finally i got what i was Searching for ☺️☺️♥️♥️
love your sir from 🇳🇵♥️

PAGALM-jyqq
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What I like about this is, the same skills by which you find the derivative will come into play again when you do epsilon-delta.

For a more general proof of the derivate of x^a, I had to resort to logarithmic differentiation.

kingbeauregard
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Great explanation thank you! What chalk do you use? It looks amazing by the way.

ejc
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Is it possible to use the same principle to prove the derivation rule for generic radials (derived from the nth root)?

EnzoMariano
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The coolest maths teacher I've ever seen 😎👍Your explanations are very clear and easy to understand 😊 Thank you for such lovely videos 😇

prakrit
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All first principle videos: Square root, all arctrig except arccot, plus some other various functions. Gotta say, I feel like a bit of a teachers pet doing this, he has a playlist. But its here for the record too

JourneyThroughMath
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i did this by using newton's binomial theorem to expand (x+h)^(1/2) but then i realized you can just multiply by the conjugate 😅😅

Samir-zbxk
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I've always wondered: why does the limit definition give the slope? Perhaps I never fully understood it, l'm in Calc3 now, but it seems like you'd get 0 in the denominator, of course that's undefined. Logically, it makes sense, but it's just never worked conceptually in my head.

DefenderTerrarian
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Where is the 1/root x derivative video? I can't find it on your channel sir.

ThOneWhoWaits
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Please explain the derivative of a factorial function

doctorno
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... f'(X) = LIM(h -> 0) [ SQRT(X + h) - SQRT(X) / h ] ... [ rewriting the denominator in its original form ... h = (X + h) - X ] .... LIM(h -> 0) [ SQRT(X + h) - SQRT(X) / ( (X + h) - X ) ] .... now treating the denominator as a Difference of 2 Squares as follows ... h = (X + h) - X = ( SQRT(X + h) - SQRT(X) )( SQRT(X + h) + SQRT(X) ) ... observing a common factor ( SQRT(X + h) - SQRT(X) ) between numerator and denominator, so after cancelling this factor we obtain the solvable LIMIT form ... f'(X) = LIM(h -> 0) [ 1 / ( SQRT(X + h) + SQRT(X) ) ] = 1 / ( SQRT(X) + SQRT(X) ) = 1 / 2*SQRT(X) ... the derivative of f(X) = SQRT(X) ...

jan-willemreens
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Should we as viewers scower your videos to see which principles you havent done

JourneyThroughMath