Circles Tricks | Circle Full Concept/Formula/Questions/Short Tricks | Circle Class 9/10/11 | Dear Si

Hey!

In this video, we are going to learn Circle from basic to advance. We have covered this chapter in a very unique way, any student who has a circle chapter in his class can learn it easily. Also, we have considered the level of your questions and concept, so we have designed this video from the initial class to a higher one. If you are in 9th, 10th, 11th, or any other class but you are willing to learn circle, this video will be playing a very crucial role in your preparation.

Now the question is if you are preparing for the government examinations then what is for you in this video? The answer is you will be able to complete this chapter with basic to advance understanding and this video will help you to save time in examinations. Go with the video, watch till the end, make some notes and share with your friends.

Also, Watch

Share this video among your friends and do practice because practice makes men perfect.

Follow us at:-

2. Instagram:-

Here are the Key Moments of the video 👇

00:00 Intro of the Video
01:05 Circle Concept
04:41 Quick Recap
05:33 Circumference of a Circle
08:08 Area of Circle
09:53 Area of Semicircle
10:33 Area of Quadrant
11:04 Area Enclosed by Two Concentric Circles
13:35 Arc and Chord
16:45 Major Segment and Minor Segment
18:02 Major Sector and Minor Sector
20:23 Important Formulas & Remembering Trick
27:33 Circles Question 1
31:33 Circles Question 2
36:37 Circles Question 3
40:10 Circles Question 4
46:58 Circles Question 5
51:40 Outro
-----Thank You for Watching-----
Team “Dear Sir"

[pratul.babar]

Circles ke sare THEOREMS ke uppar eak video bana do.

[sahilsonule]

The Students who see my comment I wish you will get 90% + in boards

[thatonerandomguy]

41:10
The answer is 68/7 cm²

Explanation : area of square = side²
Side= 4
Area = 4² = 16cm²

Area of circle = πr²
As there are 2 circles including 4 quadrants of a circle reassembling 2 circles so the formula should be 2πr²

So area of 2 circles = 2πr²
= 2×22/7×1². (r=1)
= 44/7

Area of shaded region = area of square - area of 2 circles

So area of shaded region =
16 - 44/7
=( 112-44)/7 (I multiplied 7 to the numerator and denominator of 16/1)

= 68/7 cm²
I think this is correct ☺️
Hope it helps everyone 🙋

[aashuprajapati]

Ye comment in logo k liye jo likhte h KON KON APNE MATA PITA KO BHAGWAN MANTA HAI KON MAA SE PYAAR KARTA H TOH unhe samjha du hum toh pagal hai hum sab pagal hai bas tu saccha hai jo bhagwan Manta hai pata nahi sab videos k niche ye hi comment milta hai sar dard ho jata Galti tumhari nhi h galti toh humari hai

[beawesome]

I am Also in 10th class, I am wishing all my batchmates that they will score best this year because of *Dear* *Sir*🎊🎉🙏😇🙂

[haveagoodday]

The one who read my comment
I wish you to get *95%* in board👏

[spsingh_]

My father: Go and study📔📖
Me: Give me mobile 📱
Father: But why🤔
Me: Study matlab Dear sir😂😂

[VinodKumarSharma-hxmx]

IN MATHEMATICS! HE IS THE MOST FRIENDLY TEACHER

[rishupandey]

circle ke sare theorems ka ek separate video bna do sir
AGREE FRIENDS！！！！
LIKE👍👍

[underdoggames]

Sir we want all ncert maths chapters explination in dear sir style

[Abhishekvlogs]

Sir eak video
Surface area and volume

👇Agree like here.

[rohitrawat]

I have no words to thank you ... Outstanding 😎🤞

[Anonymous-kbkt]

Circle's circumference=2πr
Area of circle= πr² (09:46)
Area of semicircle=1/2 ×πr²
Area of quadrant=1/4 ×πr²
The area enclosed by two concentric circles= πR²-πr²{ where R is the radius of a big circle and r is the radius of a small circle} (12:15)
Length of Arc= (∅/180 ×πr)
Area of sector= ∅/360 ×πr²
Area of segment= r²[π∅/360 -1/2 sin∅] (27:39)

[sipaheelal]

Newton's fourth law of motion 😂😂 :-
Every book continues to be in state of rest and covered with dust until and unless internal and external exam appears and the speed of the page turning is directly proportional to the syllabus to be covered and tension in mind remain constant.

[theprencydiaries]

40:58 ( hw ques ) : Solution :- Area of the remaining portion :
Area of square – 4 ( Area of each quadrant of a circle ) + Area of circle
= ( side)^2 - 4 * ¼ πr^2 + πr^2
= ( side)^2 - πr^2 + πr^2
= ( side)^2 - 2 πr^2
= ( 4 )^2 - 2* 22/7 * 1^2
= 16 – 44/7
= 16/1 - 44/7
Now, take LCM of 1 and 7.
So, it would be = (16 × 7 - 44) /7
= (112 - 44)/7
= 68/7

= 9.7 cm^2

Therefore, area of the remaining portion is 9.7 cm^2.

[RyZenFalL_official]

Q3: Area of shaded region=Area of square- Area of 4 quadrant(1 circle)-Area of circle where a=4cm, r=1cm=(4)2- pir2-pir2=16- 3.14-3.14(integer value of pi)=9.72

[jyotirajak]

Wow...
I am shocked .
I cannot resist subscribing his channel, I have never seen such a best maths teacher.

[ishabhartiyt]

For concept watch 00:30 -28:00
For questions on circle 🔴⭕ watch after 28:00🙃🙃🙃

Thx a lot sir

[naturalearth]

Sir please class 9th ke chapter 10 all chapter ki video bna dijiye please. 🙏
You are the best teacher ever.

[lionelmessi]

Dear sir....can u plzz do something about the 10th class " construction", "area related to circle" and "statistics".