Deriving e from the limit (1+1/x)^x as x approaches infinity

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You cant use ln in your proof since ln is based on e and its derivative is based on the results of this theorem.
The actual proof is complicated and it just proves the limit exists and is between 2 and 3, than it is calculated with taylor approximation

Ursus-tllt
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hello, thank you for your video, but I am confused about how you canceled the -1/x^2.

isabellamichalek
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You can not use natural logarithm as E is to be proved. Dhanyavad

prakashlakhapate
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What I'd be interested in knowing is what happens if 1/x is replaced by 2/x, or 3/x. Since the given formula converges and one factor is being multiplied by a constant, the new formula should also converge.

jamesharmon
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I understood all, but at the beguining, why there is (let y) what meaning ?, and what ln y =

DamienBlt
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Idk, there was a n easier method imo, where by using log properties and mclaurin you not only simplify the process but also save up time.

РусскийПатриотЯша
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I am getting stuck like why are we cancelling -1/x^2 won't those two be equal to 0 and we cannot cancel 0 terms like that
Please correct me if I am wrong

AbhilashKhuntia
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but isn't this limit the definition of e? or are you using the infinite polynomial definition of e^x

wyboo
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What will happen if base is 10? ( Then we have log 10 = 1 )

willyprophete
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Binomial expansion formula need to be used because e is to be proved.

prakashlakhapate
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I just discovered your channel. You are doing a wonderful job. Do you have a Whatsapp or telegram group for Jss1 student's mathematics

sweetworldismine
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ln == log base e, and e is defined by this limit, so nothing was achieved other than showing consistency - there is no need to prove anything, as the definition of e itself is the limit

adwz
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logy = 1 and then y = 10 or lim xlog(1+1/x) = 10 when x is very bigger

willyprophete