Solving a Rate Law Using the Initial Rates Method

[Nickeo]

For anyone confused about the last part. First he solved for k given experiment 1. Given rate equation: Rate= k[P4]^2. First isolate k: K=rate/[P4]^2. Then plug in experiment 1 data which is k=(3.19*10^-4)/(0.0110)^2 = 2.636 = 2.64. Then plug in 2.64 to the original rate equation to look like this: Rate = 2.64*[P4]^2. Question c is asking to solve for the rate given P4 and H2 concentrations. Plug in both (H2 will end up being just 1 since H2^0 = 1 which is why I didn't write it before). The equation should look like this: Rate = 2.64*[0.242]^2. This equals 0.155. Thanks!

[efdrivp]

Pls can u do the calculations and not just give us the answers.l didn't get how u arrived at the answer

[aidan]

Would appreicate if if on later videos you did the calculations and not just gave the answer. The math is the only hard part for me, and so I didn't learn anything

[zodvind]

U know the teacher be cookin when they make an educational vid in this format. Honestly love paper users.

[zaaraalam]

this was the most helpful video ive ever seen thank you

[jameslengwe]

Well explained. Thank you very much 💕🙏

[dexterbalante]

im confused where did you get 4 in p4?

[AnaPaula-ybui]

Wow, i'm so grateful with your contain, it helps me a lot, thank you so much

[daniellai]

Do you have a video explaining the units? I’m confused on that part.

[MireraNYAMWEYA]

Me taking chemical kinetics class this semester and not getting nothing in the lectures and understanding everything here makes me wanna question my life

[noorjahanshaik]

Can you please explain with some clarity