Algebra II Lesson II.4: Age Word Problems I

In this video, we look at two examples that show how to set up and solve an age word problem. This type of algebra word problem involves finding the unknown age of one or more people.

[thejudicious]

You explained it so well but when I do it by my own. I still don't get it. I'm so dead right now.

[lanz]

Danilo's age is twice the age of Cora 4 years ago. three years from, the sum of their age will be 46. How old will Cora be 8 years from now?answer this please.

[elijahflores]

3x-18=×+2
Transpose the xs and 18
It would be
3x-x=2+18
(Transposing a no. Would change the sign +=- and vise versa)
2x=20
Then cancel 2 to division
2÷20
×=10
Thanks alot for the review sir :)

[Greenemath]

Yes, that is one of the ways to correctly set up and solve that problem. Good Job :0

[tubeblack]

It's more clear if you have columns for each age category, one for past, one for current, and, if necessary, future. I find its easier to figure out the logic this way.

[imergeo]

i really like the fact that you elaborate these problems very well but sir you need to slow down

[LorenzoOradia]

Merry Christmas! I guess life is a word problem!!!

[conradofernandez]

The sum of Robin's sage and Bruno's sage is 45. Seven years ago, Robin was 16 years more than one-half as old as Bruno then. How old is Robin now?


Please help me how to solve this easier please. thankyou in advance :)

[pitoumil]

hello. at 2:44 how did you solved that?
3 times 1=3 divided by 3= 1 = x or 1x?

[DanX-gamingK]

Please answer, if the problem said. Mike was 3 times as old as sandra. Why should not be 3(x-2)? Since (x-2) was the age of Mike 6years ago.

[violethill]

Hello do you have a solution or explanation for this problem I've found on your website? it's really confusing me


On a field trip, a teacher is trying to determine the age of three students: Aya, Molly, and Mary. She is told that four years ago, Aya was the same age as Molly is today and Aya is two years older than Mary. Additionally, she knows that the difference of Aya’s current age and Molly’s current age is the same as Mary’s age nine years ago. Help the teacher find the age of the three girls.

[elevenfairytale]

7:07 why did you have to subtract X and add 18? Is that just a rule you have to follow?

[rexpartisala]

From from this previous video you didn't taken the account of the fraction but now you did. please explain.

[nikyabodigital]

Wait you said that equation was age of sandra and mike six years ago. Then why would the answer be their current age?

[ryzalineabanag]

Do you have an solving km/h word promblem video?

[gwynethsumbiling]

How did you get the 4 sir from 3x+x= 204

[uraaxeecaqligaaga]

For the second question we can get the answer by abit different way:
Sandra= x-8
Mike= x
6 yrs ago mike was 3 times as old as Sandra.
Now Sandra =x-8-6
Mike = x-6
Let's solve for x
X-8-6= x-6= x=4
6 yrs ago Sandra was 4 yrs old and mike was 12 yrs old because he was 3 times older than her and their current age is 4+6 and 12+6 respectively which is 10 and 18 yrs .

[uabm]

For the Second problem if i used Mike's age as a variable.I had X= Mike's age and Sandra's age= x-8. So 6 years ago I had x-6 for Mike and x-14 for Sandra since 6 years ago she would be 14 years younger which gives the equation x-6=3(x-14). I got x=18 for Mike and taking 8 away from that gives me 10 for Sandra's age. Did i use to correct procedure to get this answer? Thanks.

[uraaxeecaqligaaga]

3(x+1/3x)= 68×3= 3x/1+3x/3=68×3 =3x+x=68×3 = I hope this is the way he arrived at here.

[roseb]

i got mike being 16 and sara being 8 and the right and left side of the equation still equalled each other how would i know i did it wrong?