5.2 Enthalpy cycles (SL)

Understandings:
The enthalpy change for a reaction that is carried out in a series of steps is equal to the sum of the enthalpy changes for the individual steps.
Applications and skills:
Application of Hess’s Law to calculate enthalpy changes.
Determination of the enthalpy change of a reaction that is the sum of multiple reactions with known enthalpy changes.

[nathsirisaowaluk]

This really helped clarify a lot of things for me. Thank you so much for making this!!

[meowmeow-dwbi]

good video. where are the values in 2:01 coming from? eg (6 x -394) where did we get this value? i know its 6 carbon but how did we randomly put it

[fatimalearns]

At 4:23, Sir hydrogen is elemental form so it will have is standard enthalpy change as 0 BUT since it is converting to H2O that's why we have standard enthalpy change as -572?

[masaqader]

Hello, i did not get why 1411 was positive and not negative in the end? i honestly, did not get how adding them is going to give us Y too

[UsmanAli-toru]

1:40
Are enthalpy change of formation and combustion are taking place simultaneously?

[quantaviousowandle]

if i had to build an enthalpy cycle, how would i know where to point the arrows?

[bestcomedyvideos]

4:25 could we have taken the enthalpy of formation for 2 H2 + O2 --> 2 H20 instead of combustion.... would that give the same value..?

[amalipabasarajk]

Sir, can we get the value of the formation of H2o, instead of the value of the combustion of H2 .

[patronus]

but dont individual elements have enthalpy change of 0 ? like carbon and hydrogen?