Thermodynamics L13 | Enthalpy of Formation (And More Processes) | JEE & NEET 2022 | Pahul Sir

Thermodynamics L13 | Enthalpy of Formation (And More Processes) | JEE & NEET 2022 | Pahul Sir - Advanced Problem Solving And Lecture On Thermodynamics | JEE & NEET Aspirants @7pm only on Catalysis By Vedantu.

Session In A NutShell::
Pahul Sir Covers All The Important Problems And Topics On Thermodynamics Through This Session "Thermodynamics L13 | Enthalpy of Formation (And More Processes) | JEE & NEET 2022 | Pahul Sir", So That All Of You Guys Will Be Bonded Perfectly With The Topics And Well Prepared For NEET & JEE Chemistry Exams! Master Both Long Theoretical Answers And Fast Calculation Based Problems. You Have To Be Flexible Between Solving Questions For Board Exams, JEE & NEET!

NOTE:: Thermodynamics Is The Study Of Heat, "thermo," And Work, "dynamics." We Will Be Learning About Energy Transfer During Chemical And Physical Changes, And How We Can Predict What Kind Of Changes Will Occur.

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#Thermodynamics #withme #NEETJEE2022
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[CatalysisbyVedantu]

Dear students, to make the most out of Vedantu Pro, select the plan that suits you the best.
Apply coupon code PHPRO to avail exciting discounts for both JEE and NEET
For 2022 Students:

1 Month (5, 000) @ 4, 000/ month
3 Month (13, 500) @ 3, 600/ month
6 Month (24, 000) @ 3, 200/ month
12 Month (42, 000) @ 2, 800/ month

[deepansingh]

Sir can I get prepared for KVPY and JEE if I take the subscription of vedantu pro CBSE course .

[abhiramt]

Standard enthalpy of GLUCOSE= -1260.4KJ/MOL

[Kabir_Vines]

Sir mai online sir aapko thanks bolne aaya ur awesome 🙏🙏🙏🙏

[avrpavankumar]

What makes catalysis special is pahul sir .He is an amazing teacher who simplified thermodynamics

[venkatakrish]

ans -1260.4kj sir and for comburstion of propane previous qs ans 2217kj/mol you are the approx king sir

[AjayKumar-ltio]

Wonderful teacher for chemistry for organic chemistry and physical chemistry....yo pahil sir🔥♥️

[aviralmishraofficial]

Sir, there's one question, you calculated the enthalpy for the sublimation of ice if wee provides that much heat to ice, then will that sublime directly i.e without entering its liquid state?

[Sidharth-wyuo]

Sir standard state Ka MATLAB yeh hota h na ki uski room temperature per kya state h

[prakhar]

Sir's math is like my chmeistry. Very relaxed to know.

[sangeethasivakun]

Sir ans: delta H 0F c6h12o6= -1260.4 KJ EXPLANATION: C6H12O6 = 6CO2+ 6H2O delta Hcom=sigma H0F (reactant) from -2816=(6×H0F(Co2)+6×H0F(h2o)) -(H0Fc6H20+O6) FROM: -2816=(6×-393.5) + (6×-285.9) - H0F + C6H1206 THE ANSWER IS -1260.4KJ (FOR CONSTION REACTION DeltaH0F(O2) IS CONSIDER =0)

[mehuldarak]

SOMEONE plz tell me. Are these lectures complete for JEE Adv. Can I rely on them completely?

[SURENDERKUMAR-fvhc]

HEAT OF FORMATION OF C6H12O6 WILL BE ( -1260.4 )

[CSEjn-zjed]

28:13 sir to use hess law for enthalpy the temp must be same na sir
and vapourisation of water and fusion of ice dont take place at same temp na sir
so we cont be using hess law directly na sir
using kirchoffs laws we should change enthalpy at desired temp and then add na sir

[eshi]

pahul sir.. you are my favourite chemistry teacher ever!!
Sir when will we start s-block? please reply...

[kgagan]

Answer to home work question
-1260.4 KJ/mol

[hahhaharsh]

HOF -1260 kJ.. Love you sir plz take 1 batch on paid platform.. a humble request.. I won't let you down

[atulrana]

Ans of the question : -1260.4 Kj /mol

[piran]

Sir I can't find Biomolecules in completed the lesson or not? If completed pls provide the playlist....#pahulfan❤

[lakshyakotwani]

Sir if I have not studied chemical bonding and states of matter can I directly jump to thermodynamics after studying periodic properties?