Proof: Sequence Order Limit Theorem (Inequalities and Limits) | Real Analysis

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We prove the order limit theorem for convergent sequences. This proves that convergent sequences and their limits relate to each other and real numbers as we'd expect. For example if a_n converges to a and b_n converges to b, and every a_n is less than or equal to each b_n, then a is less than or equal to b. This theorem summarizes how inequalities behave with limits. #realanalysis

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Комментарии
Автор

how should i come to the assumption and let e = |a|

KhloudAhmed-fclj
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Hi why did you replace the a(n) by a(N) at 4:36, wouldn't it have still been correct if we continued with a(n)?

michaelhunt
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Hey sir I have a question for a code question reckon you could help - For the first two digits use an odd number between 39 and 100, for the last two digits use a multiple of 10, repetition is allowed work out the total number of codes which can be made using the method

louiesaunders