Edexcel Mechanics M1/January/2019

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Edexcel IAL Mechanics M1/January/2019
WME01/01/Jan/19

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At Q.5 i'm confused, can you plz tell why the 6g didn't have any role in vertical or horizontal vectors? i mean why there wasn't any vector like 6gsin45 or others?

Mahif_
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Hello, in question 2, why do you subtract ra and rb to get rba?

TheMinitrickster
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dont we consider the the normal reaction of support P in question 4 part c?why is that so?

muhammadasjad
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can you please do june 2019?
PLEASE??
Pretty PLEaSe?? <3

adelaziz
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20:45 the 560 for the person is also reversed for the lift? ( negative 560)??

sully
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In question 2 why rba and not rab? Is there a difference anyway?

sully
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question 2 seems to be wrong because tan inverse of 7/6 is 54.88 therefore this means that the answer in the mark scheme seems to be incorrect since they wrote it as tan inverse of 6/7 and not tan inverse of 7/6 ( the right answer should be 54.88 + 270)

habibaseif
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sorry but can u explain why in question 7's last part the perpendicular line is equivalent to R and we are able to do the cosine rule there

hasanaltay
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hello, Q7 why did you put = 3ma in B and =ma in A. and what does (a) symbolize?

youhaverights
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In q2 why did we divide them by -1 I know i and j are in negative but why the values are -1

XVII
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last question there is mistake sin alpha should be 3/5 not 4/5 and cos alpha should be 4/5 not 3/5

mujeebrehman
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I don’t understand why did u do X-3 wouldn’t that only include the distance up to R not to p should it not be X+3

fishyamy
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In Q3 (b) why do we subtract 560 from the equation ?

noorahmedmohamed
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How will we assume that we have to take moment about R, we could have taken from P too.

mdsohelrana
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hello miss do u have the gce june 19 m1 mark scheme ? if not can u please solve it?

aqilausrat
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In question 4, why is reaction at P is zero in the whole question

sully
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Simastalious triangle, WWE reymasterio

yazanaldinho
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Pls change your voice its a disturbance

sandhyaedirisinghe
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please manage your voice, your quite helpful but voice is a great downside !

hibatoqeer