Algebra tricks #mathsscam #shorts #algebra

[priii]

If A+B = 12
B+C = 15
C+A = 23
Then 2(A+B+C) = 12 + 15 + 23
" = 50
A+B+C = 50÷2
= 25
Hence, the answer is 25

[poojadevi]

Very difficult question maths question

[BBSCHHETRI]

IF A+B=12
B+C=15
C+A=23
THEN A+B+C=?
A+B+B+C+C+A=12+15+23
ADD ALPHABET AND NUMBERS
2A+2B+2C= 50
2(A+B+C)= 50
A+B+C= 50/2
THEREFORE
A+B+C= 25

[pauldaniel]

Incorrect question but your logic is good. If a+b=10, b+c=20, both are acceptable but c+a=36 is mathematically not possible because maximum possible A<=10 & C<=20 so C+A<=30 this is possible but how it comes more then 30??

I like your all videos sister but it's logically not right.

[dhinakarroy]

Came here to learn math instead Learning Hindi song