Determining Molar Solubility Given Ksp

[alexanderdriscoll]

I kept double-checking and had practically convinced myself I was doing it wrong. this was a nice video, short and clear, helped clear it up! thanks a lot

[JMHSAPChemistry]

I agree with you 1.5 x 10^-3 is correct, I must have had a calculator error there. Sorry!

[robertweaver]

Thank you! I have a test today and your example helped me clear up my confusions about these problems. Once again, Thank you!! 

[JMHSAPChemistry]

Ksp and solubility product constant are the same thing (K for constant, sp for solubility product). If you don't know where the system is you can calculate a "Q" which I remember because it's like a question- we don't know if it's at equilibrium and if it isn't we don't know what part needs to shift (reactants or products). If Q and K are equal, it's at equilibrium, if Q is bigger than K, the number on top is too big (products), so it will shift towards reactants.

[UniqueQ]

I so LOVE you!!! Thank you so much!!! Have an exam today and was sick the day this material was taught

[jkula]

you should annotate it or something and say that the answers wrong... should be 1.5x10^-3 

[TanujPandya]

Thank you for this video! It is so clear and I was able to understand it immediately 😊👍

[MisterTechnologic]

Please put a correction on this video. Thought I was doing something wrong for like 20 minutes before I realized the answer was wrong

[kathryncarmichel]

very helpful! I'm in Quantitative Chemical Analysis and wasn't able to figure this out. Thank you so

[anonymous]

@schleiba Hey you know you got the molar solubility wrong right? The answer is 1.5 (10^-3)

[girliegurl]

I have a test tomorrow on this and I did not know what I was doing until after I watched this so thank you so much

[yungster_rick]

man sure would be a shame if someone were to drop a racial slur here

[ris]

you saved my ass big time! I have my final exam in an hour!! Thanks!!! :D

[omardelacruz]

x^1/3 is another way of writing radical 3. it makes it easier to plug it in to your calculator

[beeutskindeep]

I hate how she doesn't call the compound by its proper molecular name.

[ayshaanwar]

did u take 1.4x10^-8 divide that by 4
then u use the cube rood u will get 1.52x10^-3

[babarmasood]

thank u so much very helpful i am currently a freshman in college

[pathagas]

2:57 do we always have to square it, or is it just because of the 2 coefficient before the I?

[SBchicadebaile]

how do you do it without a calculator? the mcat doesn't allow calculators

[hafsah]

thank you very much, very helpful!
although, either you're doing the calculation mentally, or something is wrong with your calculator.