Prove that for z=cos𝜽+isin𝜽, 𝟏/𝒛=𝟏/(𝒄𝒐𝒔𝜽+𝒊𝒔𝒊𝒏𝜽)=cos𝜽-isin𝜽 and (𝒄𝒐𝒔𝜽−𝒊𝒔𝒊𝒏𝜽)^𝒏=cosn𝜽−𝒊𝒔𝒊𝒏𝒏𝜽

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In this video we proved the corollary for z=cos𝜽+isin𝜽, 𝟏/𝒛=𝟏/(𝒄𝒐𝒔𝜽+𝒊𝒔𝒊𝒏𝜽)=cos𝜽-isin𝜽 and (𝒄𝒐𝒔𝜽−𝒊𝒔𝒊𝒏𝜽)^𝒏=cosn𝜽−𝒊𝒔𝒊𝒏𝒏𝜽.
#PythagorasMath #DeMoivreTheorem #Corollary #Proof

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