Two Expressions With Exponentials | Can You Solve?

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[williamjrsalomao]

Dear Mr Syber I hope everything is fine with . Happy to have your voice again to help us to learn Math. Greatings from Brazil

[dan-florinchereches]

I would like to use log base 2 on both equations:
Log2(a)*(b^3+b)=5/16
Log2(a)*b=1/4
We can observe that a=1 and b=0 are not solutions and divide equations:
b^2+1=5/4
b=+-1/2
If b=1/2 then log2(a)=1/2 so a=√2
If b=-1/2 then a=1/√2

[JR]

Is your health better now? Hope it is.

[ViaanHossain]

Brother you have lost your voice and that's why you were not giving your voice in your main channel but in your second channel?? what's the intention??