Chain rule for partial derivatives of multivariable functions (KristaKingMath)

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Learn how to use chain rule to find partial derivatives of multivariable functions.

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Hi, I’m Krista! I make math courses to keep you from banging your head against the wall. ;)

Math class was always so frustrating for me. I’d go to a class, spend hours on homework, and three days later have an “Ah-ha!” moment about how the problems worked that could have slashed my homework time in half. I’d think, “WHY didn’t my teacher just tell me this in the first place?!”

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That makes me happy! I'm so glad I can help along the way! :)

kristakingmath
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I hit a mental block trying to understand this chain rule for the past few hours. Books were useless and I nearly gave up. Then came across your suggestion to use a tree to write out the individual variables. I can't believe I have now finished all exercises involving this chain rule for partial derivatives of multivariable functions part. Thank you so much.

Hercules
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You don't find such well explained videos these days, very well done and thanks.

vpr
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I have always struggled whit how to set up the chain rule under different conditions and had never seen the tree-trick. I am shore that will help me a lot in the future. Thanks for the grate video

jovaha
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you deserve a Nobel prize for your perfect explanations!!, Krista

AhmedAdenOmarDaule
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you are such an inspirational teacher and it helps that your voice is smooth as silk

vor
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OMG you explained so clearly!! Do you have videos on all Calculus 3 topics? This is life savior lol

tianaiye
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Thanks a million... you've explained abstract stuff in a realistic manner. helped me a great deal

avilcorrea
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This is excellent. I love how it didn't only teach how to crunch it out, but that you actually explained why.

Ajay-nyqb
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your voice is so nice that it makes multidimensional calculus so easy to understand

anthonyelenga
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You ma'am, are my hero. I had no idea what my professor was going on about. Thank You!

AnimeDiva
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That was 2 hours worth of lectures in 15 minutes. Thanks loads!

loller
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Without you I would have failed my midterm indefinitely but I earned a solid A with you videos. I really hope you continue to make more because you are very much appreciated!!!

ariannamanabat
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awesome lecture and VOICE....yes, your voice is so pleasing to hear and you make your lectures so easy to comprehend. I thank you so much for sharing your knowledge with us that cannot afford to pay lol, but true.

CHAYITO-iipt
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you are just so clear, until now, dint realize that this was actually simpler than the books put it. thankyou Krista!

bright
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This Tree Method to solve these complex Derivatives is OSCAR WINING METHOD

batmanvsjoker
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Amazing explanation. I was very confused by the different cases and didn't understand the differences in variable dependence until seeing this.

wtfchazpwnt
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14:38 You can go twice as fast by noting that r and theta are symmetrical with respect to s and t. (s and t can be interchanged without affecting the formulas for r and theta) So, once you have partial (z/t) you can get partial (z/s) by swapping t and s, so partial (z/s) = partial (z/t)[t <-> s]
(I only saw that when I saw both end results, then I figured out why that is)

OndrejPopp
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If only one could like and subscribe more than once. You are one of my favorite youtube teachers.

MultimodAll
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I'm not taking the class anymore....but a run a community college math center. Your plane and easy explanations are being passed on to my students. Thanks. Some things I know...I can't explain simply. :)

TheVickster