Chain rule + partial derivatives

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This video shows how to calculate partial derivatives via the chain rule. Such ideas are seen in first year university.

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Thanks! If you liked this video then I recommend my new ebook which is free to download. The link is in the description.

DrChrisTisdell

half way though ur 2nd lecture and its absolute pleasure to learn this way. U r my ideal teacher and other teachers should learn to make source of knowledge like u do in youtube.

xyzbd

Dr. may I ask why do you add the 2 partial derivatives of x and y tgt ?

IceyJunior

Hi Chris! Do you have a video outlining the proof for how the block diagram provides the equation given in 4:50? I've always known how to make and apply the diagram, but I've never know the reason behind it :(. Thanks Chris!!

matthewjames

Hi Dr.Chris wonderful video. I wonder what camera you use for this video?

victoriawilson

Thank You so much for your work. You are really a man of an idea!
As from my personal side, I am very grateful, you helped me a lot

ajantas

That's a little bit clearer than how I was taught but I need to work on it. Thanks I'll check in periodically

ciccarellom

DR Chris Firstly thank you for the time and effort you have put into this. I am about to embark on an a BHEng and Mathematics is my "weaker" area. I never truly grasped PDE. WRt the 1st ex Is there a worked answer. Using (what i think) is correct differentation ln(x) = 1/x i get

LHS

1/(x+ct) in f' and then ?. i believe the f" is -1/(x^2+2*ct*x+ct^2)

RH

1st=c/(x+c*t)
... times by c^2 shows RHS = LHS

i am basically lost getting from LHS Order 1 to Order 2.

aaronrussell

how does one solve ( dy / dx)^2 + 5y = e^x when it involves ordinary derivatives ?

michaelempeigne

Thank you so much for your video Dr Chris! It was very helpful!!!

fkm

Can you make a video on how to differentiate F(u, v)=0 partially with respect to x where u=u(x, y) and v=v(x, y).

Thank You

UG

Thank you for your wonderful comments.

DrChrisTisdell

Hi - If you look at my Playlist "A second course in university calculus" then you will find what you are looking for. Best wishes.

DrChrisTisdell

Hi Matt! A proof of a simpler version is here watch?v=hJhVLmv61yE It is all about differentiability of a function - that's the key.
See you at the L&T Forum!

DrChrisTisdell

sorry this got added to the wrong video, i have now achieved this. thankyou

aaronrussell

in our culture :
the person that taught my a work, i became his slave
so you're my master

MrDaim

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