Class 9 CBSE Maths | Chapter 2 Polynomials - One shot | Xylem Class 9 CBSE

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Hi, Sir Please do exercise based questions, which is given in textbook and upload in separate videos .

ltosjzz
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I can't believe this class is free

bjnaneshwarkini
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Given x + y = -4
To Find x³ + y³ - 12xy + 64

Answer ⬇️

[x + y = -4] can also be written as [x + y + 4 = 0]

Using the algebraic identity,
a³ + b³ + c³ - 3abc = (a + b + c) (a² + b² + c² - ab - bc - ca)
If a + b + c = 0, then a³ + b³ + c³ - 3abc = 0
So, a³ + b³ +c³ = 3abc.
Here, a = x; b = y and c = 4
a³ + b³ +c³ = 3abc = 3(x)(y)(4)
x³ + y³ + (4)³ = 12xy
Substituting the value of x³ + y³ + (4)³,
= 12xy - 12xy
= 0

HOPE THIS IS CORRECT
ANY MISTAKE LET ME KNOW 😊

mczlogger
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Given, x + y = -4

We have to find the value of x³ + y³ - 12xy + 64.

The expression can be rewritten as x + y + 4 = 0

Using the algebraic identity,

a³ + b³ + c³ - 3abc = (a + b + c) (a² + b² + c² - ab - bc - ca)

If a + b + c = 0, then a³ + b³ + c³ - 3abc = 0

So, a³ + b³ +c³ = 3abc.

Here, a = x; b = y and c = 4

a³ + b³ +c³ = 3abc = 3(x)(y)(4)

x³ + y³ + (4)³ = 12xy

The expression can be rewritten as x³ + y³ - 12xy + (4)³

= x³ + y³ + (4)³ - 12xy

Substituting the value of x³ + y³ + (4)³,

= 12xy - 12xy

= 0

Therefore, the value of x³ + y³ - 12xy + 64 is 0.

CristianoRonaldo-cov
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Sir I have doubt that if root of some number comes, then what will be it's degree
Eg: what is the degree of root 3,

ayishazainab
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Sir, please upload video of Factorization in polynomials.

ltosjzz